2

编辑：这个例子完全有效:-) Mea culpa

我需要继承实体：

/**
 * User
 *
 * @ORM\Table(name="user")
 * @ORM\Entity
 * @ORM\InheritanceType("JOINED")
 * @ORM\DiscriminatorColumn(name="type", type="string")
 * @ORM\DiscriminatorMap({"user" = "User", "worker" = "Worker", "customer" =     "Customer"})
 */
class User
{
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     */
    private $id;
   }

和儿童实体：

 /**
  * Worker
  *
  * @ORM\Table(name="worker")
  * @ORM\Entity
  */
 class Worker extends User
 { 
 }

还有我的数据库的一部分

CREATE TABLE IF NOT EXISTS `user` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
   PRIMARY KEY (`id`),
) ENGINE=InnoDB  

CREATE TABLE IF NOT EXISTS `worker` (
  `id` int(11) NOT NULL
)

ALTER TABLE `worker`
  ADD CONSTRAINT `FK_Worker_User` FOREIGN KEY (`id`) REFERENCES `user` (`id`) ON     DELETE CASCADE ON UPDATE CASCADE;

我究竟做错了什么？当我尝试使用用户实体（这不是抽象的！）时，我收到错误：Doctrine\DBAL\DBALException

An exception occurred while executing 
'SELECT t0.id AS id1, t0.name AS name2, t0.surname AS surname3, 
t0.email AS email4, t0.password AS password5, t0.phone AS phone6, 
t0.www AS www7, t0.skype AS skype8, t0.active AS active9, 
t0.datetime AS datetime10, t0.role_id AS role_id11, 
t0.company_id AS company_id12, t0.type, t13.salary AS salary14, 
t13.hourSalary AS hourSalary15, t13.parent AS parent16, t13.userGroup_id AS userGroup_id17 
FROM user t0 
LEFT JOIN worker t13 ON t0.id = t13.id 
LEFT JOIN customer t18 ON t0.id = t18.id 
WHERE t0.email = ? LIMIT 1' 
with params {"1":"info@ondrej-sejvl.cz"}: 
SQLSTATE[42S22]: Column not found: 1054 Unknown column 't13.id' in 'on clause'

为什么 t13.id columng 未知.. 它在我的数据库中

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