我正在尝试开一家银行，我正在做一个扫描仪选项，所以如果你按 1，你可以按 2 取款，你将加钱，按 3 离开银行。但是当我按 2 或 3 时，它什么也没做，我尝试 else if 但是我得到更多的错误，我不知道有什么区别。
------注意------ 我尝试取消嵌套（如果那是一个短语），但我在按钮附近的 else 上出现语法错误（我已经标记了位置）所以我不知道如何解决这个问题
import java.util.Scanner;
public class Bank {
public static void main (String [] args) {
System.out.println("Welcome To Harry's Bank");
//Pin System
System.out.println("Please Enter Your Bank Pin.");
Scanner userInput = new Scanner (System.in);
int number;
int password = 7123;
int amount = 4000;
number = userInput.nextInt();
if (number == password) {
System.out.println("Pin Accepted");
System.out.println("You Have Now Entered Harry's Bank!");
System.out.println("Press The Number Of The Option You Would Like.");
System.out.println("1.Withdraw Money.");
System.out.println("2.Put In Money");
System.out.println("3.Exit Bank");
Scanner Options = new Scanner (System.in);
int option;
option = userInput.nextInt();
if (option == 1) {
//Withdraw Money System
System.out.println("You Have £4000");
System.out.println("How Much Would You Like To Take Out?");
Scanner Input = new Scanner (System.in);
int numbere;
numbere = userInput.nextInt();
if (numbere < 4000) {
int money = amount - numbere;
System.out.println("You Have Now £" + money);
System.out.println("Thank You For Banking At Harry's Bank!");
System.out.println("Please Come Again!");
}else{
System.out.println("You Do Not Have Enough Money!");
}
}
else if (option == 2) {
//AddMoney System
Scanner AddMoney = new Scanner (System.in);
int AddMoney1;
AddMoney1 = userInput.nextInt();
int NewMoney = (amount + AddMoney1);
System.out.println("How Much Would You Like To Enter?");
System.out.println("You Now Have " + NewMoney + "!");
System.out.println("Thank You For Using Harry's Bank!");
}
else if (option == 3) {
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("");
System.out.println("Goodbye!");
}
}else{
System.out.println("Next Time Only Press 1,2 or 3!");
}
//error Here For Else "Syntax error on token "else", { expected"
}else{
System.out.println("Pin Declined!");
}
}
}