9

我有一个巨大的数据框，最后 30 行如下：

libary(data.table)

输出(p)

structure(list(DATE = structure(c(1367516015, 1367516045, 1367516075, 
1367516105, 1367516135, 1367516165, 1367516195, 1367516225, 1367516255, 
1367516285, 1367516315, 1367516345, 1367516375, 1367516405, 1367516435, 
1367516465, 1367516495, 1367516525, 1367516555, 1367516585, 1367516615, 
1367516645, 1367516675, 1367516705, 1367516735, 1367516765, 1367516795, 
1367516825, 1367516855, 1367516885), class = c("POSIXct", "POSIXt"
), tzone = ""), LPAR = structure(c(6L, 6L, 6L, 6L, 6L, 6L, 6L, 
6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 
6L, 6L, 6L, 6L, 6L, 6L, 6L), .Label = c("cigp01a4a004", "cigp01b4a002", 
"cigp01b4a004", "cigp04a4a002", "cigp04a4a004", "cigp04b4a002", 
"cigp04b4a004"), class = "factor"), ENT = c(0.5, 0.5, 0.5, 0.5, 
0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 
0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5, 0.5
), USR_SYS_CPU_PCT = c(79L, 80L, 77L, 77L, 77L, 76L, 79L, 82L, 
81L, 80L, 79L, 77L, 77L, 77L, 79L, 79L, 80L, 82L, 82L, 83L, 80L, 
81L, 80L, 78L, 78L, 83L, 86L, 87L, 88L, 87L), ENT_PCT = c(706.8, 
693.8, 570.1, 641.5, 558.5, 601.5, 674.3, 742.3, 668.9, 722.6, 
679.1, 677.2, 548.5, 644.6, 689.3, 716.1, 709.5, 767.3, 753.7, 
786.4, 684.2, 735.1, 688.2, 676.6, 645.6, 788, 859.5, 832.6, 
883.1, 872.2), PHYSICAL_CPU_USED = c(3.53, 3.47, 2.85, 3.21, 
2.79, 3.01, 3.37, 3.71, 3.34, 3.61, 3.4, 3.39, 2.74, 3.22, 3.45, 
3.58, 3.55, 3.84, 3.77, 3.93, 3.42, 3.68, 3.44, 3.38, 3.23, 3.94, 
4.3, 4.16, 4.42, 4.36), PROC_QUE = c(12L, 13L, 19L, 16L, 11L, 
13L, 17L, 14L, 9L, 10L, 12L, 13L, 16L, 14L, 22L, 17L, 17L, 17L, 
26L, 26L, 15L, 43L, 9L, 11L, 12L, 7L, 31L, 26L, 27L, 23L), RELATIVE_CORES = c(3.53, 
3.47, 2.85, 3.21, 2.79, 3.01, 3.37, 3.71, 3.34, 3.61, 3.4, 3.39, 
2.74, 3.22, 3.45, 3.58, 3.55, 3.84, 3.77, 3.93, 3.42, 3.68, 3.44, 
3.38, 3.23, 3.94, 4.3, 4.16, 4.42, 4.36), USED_CORES = c(2.7887, 
2.776, 2.1945, 2.4717, 2.1483, 2.2876, 2.6623, 3.0422, 2.7054, 
2.888, 2.686, 2.6103, 2.1098, 2.4794, 2.7255, 2.8282, 2.84, 3.1488, 
3.0914, 3.2619, 2.736, 2.9808, 2.752, 2.6364, 2.5194, 3.2702, 
3.698, 3.6192, 3.8896, 3.7932)), .Names = c("DATE", "LPAR", "ENT", 
"USR_SYS_CPU_PCT", "ENT_PCT", "PHYSICAL_CPU_USED", "PROC_QUE", 
"RELATIVE_CORES", "USED_CORES"), class = "data.frame", row.names = c(NA, 
-30L))

当我喜欢使用 data.table 计算一些值时，如下所示：

p<-data.table(p)
p<-p[,RELATIVE_PERCENT:=ifelse(ENT_PCT>100, (USED_CORES/ENT)*100, USR_SYS_CPU_PCT), by= c("DATE", "LPAR")]

我收到此错误：

Error in `[.data.table`(x, , `:=`(RELATIVE_PERCENT, ifelse(ENT_PCT > 100,  : 
  Type of RHS ('integer') must match LHS ('double'). To check and coerce would
  impact performance too much for the fastest cases. Either change the type of
  the target column, or coerce the RHS of := yourself (e.g. by using 1L instead
  of 1)

这个错误是什么意思？我怎样才能绕过这个错误？

4

2 回答 2

10

问题是您的ifelse语句返回integer一些值的类型和numeric一些其他条目的 (double)。并data.table抱怨列类型中的不匹配，因为它期望用户执行强制（出于错误中给出的性能原因）。因此，只需将其包裹起来，as.numeric以便所有值都将转换为双精度值。

p <- p[,RELATIVE_PERCENT := as.numeric(ifelse(ENT_PCT>100, (USED_CORES/ENT)*100, 
                      USR_SYS_CPU_PCT)), by= c("DATE", "LPAR")]
于 2013-05-03T14:28:43.663 回答
3

我这样做了：

sapply(p, class)

并注意到我的一列是整数。然后我这样做了：

x<-x[,RELATIVE_PERCENT:=ifelse(ENT_PCT>100, ((USED_CORES/ENT)*100), as.numeric(USR_SYS_CPU_PCT)), by= c("DATE", "LPAR")]

这是钱

于 2013-05-03T14:30:23.950 回答