python - 在python中拆分大括号分组字符串

Question

感谢使用单行成语帮助有效地执行以下操作。

我有一个由大括号分隔的组的字符串，如下所示：

{1:xxxx}{2:xxxx}{3:{10:xxxx}}{4:xxxx\r\n:xxxx}....  

如何将其转换为字典格式？

dict={1:'xxx',2:'xxxx',3:'{10:xxxx}'},4:'xxxx\r\n:xxxx'}  

Answer 1

r = """(?x)
{
    (\w+)
    :
    (
        (?:
            [^{}]
            |
            {.+?}
        )+
    )
}
"""

z = "{1:xxxx}{2:xxxx}{3:{10:xxxx}}{4:'xxxx'}"
print dict(re.findall(r, z))

# {'1': 'xxxx', '3': '{10:xxxx}', '2': 'xxxx', '4': "'xxxx'"}

如果需要，请随意转换为单行 - 只需(?x)从正则表达式中删除所有空格。

上面只解析了一层嵌套，为了处理任意深度，考虑支持递归模式的更高级的正则表达式模块：

import regex

r = """(?x)
{
    (\w+)
    :
    (
        (?:
            [^{}]
            |
            (?R)
        )+
    )
}
"""

z = "{1:abc}{2:{3:{4:foo}}}{5:bar}"
print dict(regex.findall(r, z))

# {'1': 'abc', '2': '{3:{4:foo}}', '5': 'bar'}

Answer 2

我会这样做：

raw = """{1:xxxx}{2:xxxx}{3:{10:xxxx}}{4:'xxxx\r\n:xxxx'}"""

def parse(raw):
    # split into chunks by '}{' and remove the outer '{}'
    parts = raw[1:-1].split('}{')
    for part in parts:
        # split by the first ':'
        num, data = part.split(':', 1)
        # yield each entry found
        yield int(num), data

# make a dict from it
print dict(parse(raw))

'{10:xxxx}'就像在您的示例中一样，它保留为字符串。