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我正在为一个包含“info”类型信息的简单数据库编写代码。

这是我的代码:

#include <string.h>
#include <stdio.h>
#include <stdlib.h>


#define NAME_LENGTH 20
#define EMAIL_LENGTH 15

struct info {
    char name[NAME_LENGTH];
    char email[EMAIL_LENGTH];
    int flag;
};

int createDB(char *name) {
    FILE * file = fopen(name, "w+b");
    return fclose(file);
}

FILE *openDB(char *name) {
    FILE* file = fopen(name, "r+b");
    if(file != NULL) return file;
    return NULL;
}

int closeDB(FILE *f) {
    return fclose(f);
}

struct info *get(FILE *file, int index) {
    struct info* temp;
    fseek(file, index*sizeof(struct info), SEEK_SET);
    fread(temp, 1, sizeof(struct info), file);
    if(feof(file) != 0) return NULL;
    return temp;

}

int put(FILE *file, int index, struct info *record) {
    fseek(file, index*sizeof(struct info), SEEK_SET);
    int res = fwrite(record, 1, sizeof(struct info), file);
    if(res) return 0;
    else return EOF;
}

struct info *search(FILE *file, char *name) {
    int k = 0;
    struct info* temp = get(file, 0);
    do {

        if(temp -> flag == 1 && strcmp(temp -> name,name) == 0) return temp;
        k++;
        temp = get(file, k);

    }while(temp != NULL);

    return temp;
}

当我从文件中“放置”、“获取”信息时,一切正常。但是,当我尝试根据名称搜索时,我收到Segmentation fault (core dumped)错误。

请你在这里显示我的错误好吗?

4

1 回答 1

5

编码

struct info* temp;
...
fread(temp, 1, sizeof(struct info), file);

inget尝试将sizeof(struct info)字节写入未初始化的指针temp。您需要为temp.

最简单的方法可能是修改 的签名get以允许调用者使用info其堆栈中的实例

int get(FILE *file, int index, struct info *record) {
    fseek(file, index*sizeof(*record), SEEK_SET);
    fread(record, 1, sizeof(*record), file);
    if(feof(file) != 0) return -1;
    return 0;
}

这可以称为

struct info record;
if (get(file, 0, &record) == -1) {
    /* eof */
}
于 2013-05-03T08:59:06.067 回答