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我有网络音频 api 和 JQuery 旋钮库工作......但不完全。旋钮滑块控制输入滑块，但该值似乎没有传递给我想要影响的参数。

一个简单的例子见这里：

http://jsfiddle.net/RKH35/1/

代码：

<input  id="gain1" type="range" class="dial" >


<script>

document.getElementById('gain1').addEventListener('change', function() {
gainNode.gain.value = this.value;
}); 

$(function() {

        var  value = document.getElementById("gain1").value;
        $(".dial").knob({ change : function (value) {    } 

                })
});


context = new webkitAudioContext();     


//Create oscillator object & params       
oscillator = context.createOscillator(),         oscillator.type = 2;      oscillator.frequency.value = 200;


//Create gain object & params
gainNode = context.createGainNode();       gainNode.gain.value = 1;  


//Connect devices
oscillator.connect(gainNode); 
gainNode.connect(context.destination);
oscillator.start(0); 

</script>
4

1 回答 1

1 
$(".dial").knob({ 
    change : function (value) {
        gainNode.gain.value = value;
    } 
})
于 2013-05-03T08:15:14.737 回答