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我与 JSF 和 Spring Security 合作。我使用自定义登录页面。我有两个角色：管理员和用户。我的问题是如何针对不同的角色重定向到不同的页面。例如，如果用户是管理员，他将被重定向到“dashboard_Admin.jsf”，如果他是简单用户，他将被重定向到“dashboard_user.jsf”。

这是我的弹簧安全文件：

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:security="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans 
                http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                http://www.springframework.org/schema/security 
                http://www.springframework.org/schema/security/spring-security-3.1.xsd">



<security:http auto-config="true" use-expressions="true">
    <security:intercept-url pattern="/pages/**"
        access="hasRole('ROLE_ADMIN')" />
    <security:form-login login-page="/login.jsf"
        authentication-failure-url="/login.jsf?error=true"
        default-target-url="/pages/admin/dashboard_Admin.jsf" />
    <security:logout logout-success-url="/login.jsf"
        delete-cookies="JSESSIONID" invalidate-session="true" />
    <security:session-management
        invalid-session-url="/login.jsf">
        <security:concurrency-control
            max-sessions="1" error-if-maximum-exceeded="true" />
    </security:session-management>
</security:http>


<security:authentication-manager alias="authenticationManager">
    <security:authentication-provider>
        <security:user-service>
            <security:user name="test" password="test"
                authorities="ROLE_USER" />
            <security:user name="sam" password="sam" authorities="ROLE_ADMIN" />
        </security:user-service>
    </security:authentication-provider>
</security:authentication-manager>

这是我的 doLogin 方法：

 public String doLogin() throws ServletException, IOException {

    ExternalContext context = FacesContext.getCurrentInstance().getExternalContext();

    RequestDispatcher dispatcher = ((ServletRequest) context.getRequest())
            .getRequestDispatcher("/j_spring_security_check?j_username=" + username
                            + "&j_password=" + password);

    dispatcher.forward((ServletRequest) context.getRequest(),
            (ServletResponse) context.getResponse());

    FacesContext.getCurrentInstance().responseComplete();

    return null;
}
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1 回答 1

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我找到了一个不使用 Spring Security 的非常简单的解决方案，而且效果很好。谢谢拉维_

于 2013-05-03T16:53:53.923 回答