在Type Families 的 Haskell wiki 页面上,有以下示例列表:
type family F a :: *
type instance F [Int] = Int -- OK!
type instance F String = Char -- OK!
type instance F (F a) = a -- WRONG: type parameter mentions a type family
type instance F (forall a. (a, b)) = b -- WRONG: a forall type appears in a type parameter
type instance F Float = forall a.a -- WRONG: right-hand side may not be a forall type
type instance where -- OK!
F (Maybe Int) = Int
F (Maybe Bool) = Bool
F (Maybe a) = String
type instance where -- WRONG: conflicts with earlier instances (see below)
F Int = Float
F a = [a]
type family G a b :: * -> *
type instance G Int = (,) -- WRONG: must be two type parameters
type instance G Int Char Float = Double -- WRONG: must be two type parameters
这表明这type instance where
是此扩展名下的有效语法。但是,以下代码无法使用 GHC 7.4.2 为我编译:
{-# LANGUAGE TypeFamilies #-}
type family F a :: *
type instance where
F (Maybe Int) = Int
F (Maybe Bool) = Bool
F (Maybe a) = String
错误信息是:
test.hs:4:15:输入“where”时解析错误
由于这是一个解析错误,看起来该语法不受支持,所以我是否缺少必要的扩展,或者还有其他问题?