0

我有一个 arraylist ,其中记录存储为对象。我想知道是否有办法在不删除现有记录的情况下更新数组列表中的记录?

例如,我的记录具有名字、姓氏、姓名缩写、id 等属性。有没有办法更新记录中的名字,而不必同时提供所有其他属性值?

目前我所做的是,当用户给出一个 id 时,我会发现该 id 是否与数组中的任何记录匹配,如果匹配,我将其从数组中删除并让用户从头开始输入所有详细信息。

4

6 回答 6

2

Arraylist 存储引用并且不复制/创建新对象。如果更改存储的对象引用,它也会反映在 arrayList 中。这是一个示例代码来演示:

package arraylistExample;

import java.util.ArrayList;

/**
 * Class represeting entity to be stored in Arraylist 
 * 
 */
class Person {

private String name;
private int age;
private String address;

public Person(String name, int age, String address) {
    super();
    this.name = name;
    this.age = age;
    this.address = address;
}

public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
public int getAge() {
    return age;
}
public void setAge(int age) {
    this.age = age;
}
public String getAddress() {
    return address;
}
public void setAddress(String address) {
    this.address = address;
}

@Override
public String toString() {
    return "Person [name=" + name + ", age=" + age + ", address=" + address
            + "]";
}


}

.

/**
 * Public class to run the demo
 *
 */
public class ArraylistObjectModify {

public static void main(String args[]) {

    // Add an arraylist and add elements to it
    ArrayList<Person> personList = new ArrayList<Person>();
    personList.add(new Person("Juned",32,"Bangalore"));
    personList.add(new Person("Ahsan",31,"Delhi"));
    personList.add(new Person("Sniper",1,"Grave"));

    //Print list elements before change
    System.out.println("Arraylist pre objects modification");
    System.out.println("----------------------------------");
    for(Person person:personList) {
        System.out.println(person);
    }

    for(Person person:personList) {
        if(person.getName().equals("Juned")) {
            person.setName("ChangedJuned");
            person.setAddress("Hola-lulu");
        }
    }

    //Print list elements after change
    System.out.println("Arraylist post objects modification");
    System.out.println("----------------------------------");
    for(Person person:personList) {
        System.out.println(person);
    }


}

}
于 2013-05-02T12:16:11.540 回答
0

如果您的记录是一个包含可变字段(getter 和 setter)的对象,例如名称...通过某个标识符查找对象,然后使用新值调用 setter 来替换旧值。

于 2013-05-02T12:05:03.750 回答
0

使用 set() 方法。

表单 Java API 文档:

set
public E set(int index,
             E element)
Replaces the element at the specified position in this list with the specified element.

取自这里

于 2013-05-02T12:05:51.073 回答
0

如果你想更新一两个值,你可以使用 setter。如果您知道当前对象的索引,那么您可以将新对象添加到该索引,例如:- Arraylist.add(index, element) 这将更新现有元素。

于 2013-05-02T12:06:25.177 回答
0

您的对象应该包括一种设置/获取其属性的方法,可以是直接访问它们,也可以通过 set/get 方法。

例如

ArrayList<YourObject> Records = new ArrayList<YourObject>();

//Loop through your ArrayList and check if their ID attribute matches
for(YourObject record : Records) {
    if(record.id == userGivenID) {
        //prompt the user to change whichever values you want 
        Scanner s = new Scanner(System.in);
        System.out.print("Change the name of this record > ");
        record.setName(s.nextLine());
        ...etc...
    }
}

使用 get/set 方法是一种很好的做法,例如

record.setName("Bob");
String name = record.getName();
于 2013-05-02T12:10:06.680 回答
0
// Check this example

public class Test {
    public static void main(String[] args){
        List<Student> al = new ArrayList<Student>();

        Student s1 = new Student(1, "John", "Nash", "N");
        Student s2 = new Student(2, "John", "Slash", "s");

        al.add(s1);
        al.add(s2);


        for(Student s:al){
            if(s.getId() == 2){
                s.setfNmae("Nks");
                al.add(al.indexOf(s), s);
            }
           s.display();
        }

    }
}

class Student{
    private int id;
    private String fName;
    private String lName;
    private String initial;

    Student(int id, String fName, String lName, String initial){
        this.id = id;
        this.fName = fName;
        this.lName = lName;
        this.initial = initial;
    }
    void display(){
        System.out.println(id);
        System.out.println(fName);
        System.out.println(lName);
        System.out.println(initial);
    }

    /**
     * @return the id
     */
    public int getId() {
        return id;
    }

    /**
     * @param id the id to set
     */
    public void setId(int id) {
        this.id = id;
    }

    /**
     * @return the fNmae
     */
    public String getfNmae() {
        return fName;
    }

    /**
     * @param fNmae the fNmae to set
     */
    public void setfNmae(String fNmae) {
        this.fName = fNmae;
    }

    /**
     * @return the lName
     */
    public String getlName() {
        return lName;
    }

    /**
     * @param lName the lName to set
     */
    public void setlName(String lName) {
        this.lName = lName;
    }

    /**
     * @return the initial
     */
    public String getInitial() {
        return initial;
    }

    /**
     * @param initial the initial to set
     */
    public void setInitial(String initial) {
        this.initial = initial;
    }
}
于 2013-05-02T12:25:35.877 回答