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当我在 python shell 中一一键入命令时，此用于从 url 下载 json 文件的代码运行良好。但是，当我尝试运行包含此代码的模块时，我得到：ValueError: No JSON object could be decoded. 任何想法为什么会这样？我运行python 2.7。

import urllib2
from urllib2 import Request
import json
import re

url1 = "http://www.skyscanner.net/flights/lond/nyca/130514/130525/airfares-from-london-to-new-york-in-may-2013.html"

req = Request(url1)
res = urllib2.urlopen(req)
the_page = res.read()
theText = str(the_page)

myre = re.compile(r'"SessionKey":"((([a-z0-9]+-)+)[a-z0-9]{12})"')
match = re.search(myre, theText)

print match.group(1)

url2 = "http://www.skyscanner.net/dataservices/routedate/v2.0/"+str(match.group(1))
htmltext = urllib2.urlopen(url2)
data = json.load(htmltext)

现在整个代码：

import urllib2
from urllib2 import Request, urlopen, URLError, HTTPError
import json
import re


url1 = "http://www.skyscanner.net/flights/lond/nyca/130514/130525/airfares-from-london-to-new-york-in-may-2013.html"

req = Request(url1)
res = urllib2.urlopen(req)
the_page = res.read()
theText = str(the_page)

myre = re.compile(r'"SessionKey":"((([a-z0-9]+-)+)[a-z0-9]{12})"')
match = re.search(myre, theText)

url2 = "http://www.skyscanner.net/dataservices/routedate/v2.0/%s" % str(match.group(1))

req2 = urllib2.Request(url2)

try:
    response = urlopen(req2)
except HTTPError as e:
    print 'The server couldn\'t fulfill the request.'
    print 'Error code: ', e.code
except URLError as e:
    print 'We failed to reach a server.'
    print 'Reason: ', e.reason
else:
    data = json.loads(response.read())

print data["SessionKey"]
4

1 回答 1

0

哈！你是对的，这是shell使用和脚本使用之间的区别。无论url1在做什么，在您打开时它还没有（远程）完成url2。只需短暂的等待时间即可完成所有工作！

import time

url2 = "http://www.skyscanner.net/dataservices/routedate/v2.0/%s" % str(match.group(1))

time.sleep(5)

req2 = urllib2.Request(url2)

所以这根本不是你的代码……哼哼！

于 2013-05-02T13:34:57.350 回答