0

我有两个数组 $fuel 和 $hours，具有相同数量的数据，我想将它们同时插入数据库中。

这是我所拥有的：

$fuellength = count($fuel);
$f = 0;             

for($f=0;$f<$fuellength;$f++){ 
if ($fuel[$f] > 0){
    if (
    mysql_query("INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')");
        ) 
        echo "data has been inserted"; 
     else 
        echo "data has not been inserted";
 } //end if 
}//end for

它什么也没告诉我！对数组使用“for”循环是否正确？还是我应该只使用“foreach”？如果是这样，我如何循环同时抛出两个数组？

提前致谢！此致

4

4 回答 4

0

假设您已经与 MySQL 服务器建立了连接：

$cn = mysql_connect("hostname", "username", "password");

假设您选择了数据库：

mysql_select_db("databasename", $cn);

你的逻辑是正确的。但是您的 SQL 插入顺序与您的字段不匹配。您正在尝试将$fuel[$f]数据插入date_hour字段。

$f = 0;
$added = 0; 
$noAdded = 0;             

while($f < count($fuel))
{ 
    if ($fuel[$f] > 0) 
    { 
        if(mysql_query("INSERT INTO grafiku 
                   (vehicle_plate,   fuel_level,    date_hour) 
            VALUES (".$userid.",   ".$fuel[$f].", '".$hours[$f]."')"
        ))
            $added++; 
        else 
            $noAdded++;
    }

    $f++;
}

//Then you can display additional information after inserting is done. 

echo $added . " data has been added to table.";
echo "<br />";
echo $noAdded . " data could not be added to table.";
于 2013-05-02T08:39:43.400 回答
0

如果您的代码与此完全相同，您将看不到任何内容，因为您有一个致命的 php 错误。你有一个ELSE没有起始声明的IF声明。从您的IF声明中删除评论，它应该再次起作用。

于 2013-05-02T08:28:55.750 回答
0

你的代码有错误，Parse error: syntax error, unexpected T_ELSE in <file name> on line 12

<?php

   $fuellength = count($fuel);
   $f = 0;             

  for($f=0;$f<$fuellength;$f++){ 
  if ($fuel[$f] > 0){
  if (mysql_query("INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES     (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')")) 
    echo "data has been inserted"; 
     else 
    echo "data has not been inserted";
 } //end if 
 }//end for
?>
于 2013-05-02T08:47:06.547 回答
0 
$fuellength = count($fuel);
$f = 0;             

for($f=0;$f<$fuellength;$f++){ 
if ($fuel[$f] > 0){
    $qryStr = "INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')";
    echo $qryStr."/br"; 
 } 
}

检查您是否正在获取查询和值。

于 2013-05-02T08:34:24.753 回答