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我正在尝试调用此 Web 服务的方法 getWeather():http ://www.webservicex.com/globalweather.asmx?WSDL

这是我的代码:

public class ServiceCall {
private static final String NAMESPACE = "http://www.webserviceX.NET";
private static final String URL = "http://www.webservicex.com/globalweather.asmx";

public String prova(String citta){
        final String SOAP_ACTION = "http://www.webserviceX.NET/GetWeather";
        final SoapObject requestObject=new SoapObject(NAMESPACE,"GetWeather");   

        PropertyInfo pi = new PropertyInfo();
    pi.setName("CityName");
    pi.setValue(citta);
    pi.setType(String.class);
        requestObject.addProperty(pi);

  SoapSerializationEnvelope envelope=new SoapSerializationEnvelope(SoapEnvelope.VER11);

        Marshal floatMarshal = new MarshalFloat();
        floatMarshal.register(envelope);

        envelope.setOutputSoapObject(requestObject);

        HttpTransportSE androidHttpTransport =  new HttpTransportSE(URL);
   androidHttpTransport.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
     String res="";

      try{
        androidHttpTransport.call(SOAP_ACTION, envelope);
        SoapObject response = (SoapObject)envelope.bodyIn;
        res=response.getPropertyAsString("Body");
     }catch(Exception e){Log.d("Prova",e.toString());}
     Log.d("Prova", res);
      return res;
 }

}

但我得到这个异常:java.io.IOException: HTTP request failed, HTTP status: 500

我哪里错了?

4

1 回答 1

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private static final String NAMESPACE = "http://www.webserviceX.NET";

应该private static final String NAMESPACE = "http://www.webserviceX.com";

并且final String SOAP_ACTION = "http://www.webserviceX.NET/GetWeather"; 应该是final String SOAP_ACTION = "http://www.webserviceX.com/GetWeather";

如果我弄错了,请告诉我。

于 2013-05-01T20:27:04.740 回答