我有一个创建基本表格布局结构的脚本,我正在尝试使用 AJAX 和 jQuery 将该脚本的输出输入到 TinyMCE 文本区域。我用 PHP 编写了脚本,如果我直接打开脚本,它就可以很好地工作。
我想要做的是让用户从下拉列表中选择一些东西(在这种情况下是一个产品),它会返回一个包含该产品相关数据的表格。我使用以下脚本将其插入到 textarea 中:
$('#product_id').change(function(e) {
product_id = $(this).val();
$.ajax({
url: 'http://<? echo $_SERVER['HTTP_HOST']; ?>/includes/ajax.php',
type: 'POST',
data: { product_choice: true, product_id: product_id },
success: function(data) {
$('#mce_1').val(data);
}
});
});
'data' 确实返回,但是当它被放置在 tinyMCE 文本区域中时,它显示以下错误(脚本继续并输出表格):
警告:在第 71 行的 /home/sites/very-dev.co.uk/public_html/cms/includes/ajax.php 中为 foreach() 提供了无效参数警告:在 /home/sites/very 中为 foreach() 提供了无效参数-dev.co.uk/public_html/cms/includes/ajax.php 在第 100 行
这两个错误是: foreach($product_data as $key=>$product):和foreach($product_data as $product):
// Connect to database
$link = mysqli_connect(DBHOST,DBUSER,DBPASS,DBNAME);
// check connection //
if (mysqli_connect_errno()):
return printf("Connect failed: %s\n", mysqli_connect_error());
endif;
$col_qry = mysqli_query($link,"
SELECT column_name
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'cms_plugins_products_models'
AND column_name != 'id'
AND column_name != 'product_id';")
or die(mysqli_error($link)
);
while($col_row = mysqli_fetch_object($col_qry)):
$col_names_array[] = $col_row->column_name;
endwhile;
$qry = "SELECT product.name AS product_name, product.id, model.*, image.src AS thumb
FROM cms_plugins_products AS product
LEFT JOIN cms_plugins_products_models AS model
ON (product.id=model.product_id)
LEFT JOIN cms_plugins_products_images AS image
ON (product.id=image.product_id)
AND (image.is_thumb=1)
WHERE product.id='" . $_GET['product_id'] . "'";
$result = mysqli_query($link, $qry) or die(mysqli_error($link));
while($row = mysqli_fetch_object($result)):
foreach($col_names_array as $column):
$columns = explode('_', $column);
if($column != 'name' && $column != 'description'):
$components_qry = "SELECT name
FROM cms_plugins_products_components_" . $columns[0] . "
WHERE id='" . $row->$column . "'";
$components_result = mysqli_query($link, $components_qry) or die(mysqli_error($link));
$components_row = mysqli_fetch_object($components_result);
endif;
if($columns[0] == 'name'):
$product_data[$row->product_name][$row->name][$columns[0]] = $row->name;
elseif($columns[0] == 'description'):
$product_data[$row->product_name][$row->name][$columns[0]] = $row->description;
else:
$product_data[$row->product_name][$row->name][$columns[0]] = $components_row->name;
endif;
endforeach;
$thumb = $row->thumb;
endwhile; ?>
<table>
<thead>
<tr>
<th></th> <?
$i = 0;
foreach($product_data as $key=>$product):
foreach($product_data[$key] as $key2=>$model): ?>
<th <? if($i == 1): echo 'id="recommended"'; endif; ?>> <?
switch($i):
case 0:
echo 'Basic';
break;
case 1:
echo 'Mid';
break;
case 2:
echo 'Pro';
break;
endswitch; ?>
<div>
<img alt="<? echo $key; ?>" src="http://cms.very-dev.co.uk<? echo $thumb; ?>">
</div>
<h5><? echo $key2; ?></h5>
<p><? echo $product_data[$key][$key2]['description']; ?></p>
<a>Customise?</a>
</th> <?
$i++;
endforeach;
endforeach; ?>
</tr>
</thead>
<tbody> <?
foreach($product_data as $product):
$i = 0;
foreach($product as $model):
foreach($model as $key2=>$component): ?>
<tr> <?
if($key2 != 'name' && $key2 != 'description'): ?>
<td><? echo $key2; ?></td> <?
foreach($product as $key=>$model): ?>
<td><? echo $product[$key][$key2]; ?></td> <?
endforeach;
endif; ?>
</tr> <?
endforeach;
if($i == 0): exit(); endif;
$i++;
endforeach;
endforeach; ?>
</tbody>
</table>
这可能是一个我没有看到的非常简单的问题,对此有任何帮助吗?