3

我有一个非常复杂的 mySQL 查询,我想运行它,但我在思考如何编写它时遇到了麻烦。

基本上我有三个表:

a(aID, name);
b(bID, val);
ab(aID, bID, include)

我想要做的是创建一个创建这样的表的查询:

c(aID, percentage);

我希望以这种方式(总/可能)百分比。总计是这样计算的。每次 a 行和 b 行有关系并且包含为 1 我希望总计添加 b.val 的值。可能是 b.val 的总和,除非 ab.include = 0

例如:

a:
+-----+
| aID |
+-----|
| 1   |
| 2   |
| 3   |
+-----+

b:
+-----+-----+
| bID | val |
+-----+-----+
| 1   |   1 |
| 2   |   1 |
| 3   |   1 |
+-----+-----+

ab:
+-----+-----+---------+
| aID | bID | include |
+-----+-----+---------+
| 1   |   1 |       1 |
| 1   |   3 |       0 |
| 2   |   1 |       1 |
| 3   |   1 |       1 |
| 3   |   2 |       1 |
| 3   |   3 |       1 |
+-----+-----+---------+

c:
+-----+------------+
| aID | percentage |
+-----+------------+
| 1   |         50 |
| 2   |      33.33 |
| 3   |        100 |
+-----+------------+

目前我有这个:

SELECT a.aID, (SUM(b.val)/(SELECT SUM(val) FROM b))*100 AS percentage
FROM a, ab, b
WHERE a.aID = ab.aID AND ab.bID = b.bID
GROUP BY a.aID

这给出了 aID 与 bID 相对于重量的百分比,但我想添加其他计算。

这可能吗?

试过这个,但没有奏效:

我正要试试这个:

SELECT a.aID, (SUM(b.val)/(SELECT SUM(val) FROM b,ab WHERE ab.include = 1))*100 AS percentage
FROM a, ab, b
WHERE a.aID = ab.aID AND ab.bID = b.bID AND ab.include = 1
GROUP BY a.aID
4

1 回答 1

4

试试这个(sqlfiddle):

SELECT ab.aID, SUM(b.val*ab.include)/(possible.possible-SUM((1-ab.include)*b.val))*100 AS percentage
FROM ab, b, (SELECT SUM(val) possible FROM b) possible
WHERE ab.bID = b.bID
GROUP BY ab.aID

分子(总计):将我们有关系的所有 b 值相加

分母(可能):从所有 b 值的总和中减去存在关系且包含为 0 的值。

于 2013-05-01T07:29:23.833 回答