ios - 检测用户是否没有触摸物体

Question

我正在为 iPad 开发 iOS 应用程序。我使用 I 代码来检测用户何时触摸对象，但现在我想使用相同的代码来检测用户何时不触摸对象。这是代码：

  - (void)touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event {
UITouch *touch = [touches anyObject];
CGPoint location = [touch locationInView:[touch view]];

if (CGRectContainsPoint(ribbon.frame, location) || CGRectContainsPoint(inferior.frame, location) || CGRectContainsPoint(superior.frame, location) & (pujat==YES)){
    pujat=NO;
    [UIView animateWithDuration:0.25 animations:^{
        superior.frame = CGRectMake(0, 710, 1024,500);
        ribbon.frame = CGRectMake(480, 685, 70,70);
        inferior.frame = CGRectMake(0, 750, 1024,500);}];

    [self.view bringSubviewToFront:inferior];

}
}

那么如何检测用户何时触摸屏幕而不是某个对象呢？

Answer 1

实际上，如果触摸点不在某个对象上，CGRectContainsPoint 将返回 false。假设您要检查触摸点是否在功能区中。只有一个“！” 就足够了。

- (void)touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event {
    UITouch *touch = [touches anyObject];
    CGPoint location = [touch locationInView:[touch view]];

    if (CGRectContainsPoint(ribbon.frame, location) || CGRectContainsPoint(inferior.frame,     location) || CGRectContainsPoint(superior.frame, location) & (pujat==YES)){

        if(!CGRectContainsPoints(ribbon.frame,location))
            NSLog("Touch point is not on ribbon");

        pujat=NO;
        [UIView animateWithDuration:0.25 animations:^{
        superior.frame = CGRectMake(0, 710, 1024,500);
        ribbon.frame = CGRectMake(480, 685, 70,70);
        inferior.frame = CGRectMake(0, 750, 1024,500);}];
        [self.view bringSubviewToFront:inferior];
    }
}