linux - Rename all files in a folder

Question

I'm on a linux, and a download a lot of funny pictures. Unfortunately, I'm left with a bunch of duplicate names like download (1) and image.jpeg. I would like to change them all to something a bit more helpful.

Is there a way to (preferably using bash) to rename all files to sequential 4 digit numbers with leading zeroes?

Eg:

0001
0002
0003
0004
....

Answer 1

上一个答案中提供的代码片段是一种优雅的方式，但拼写错误或外壳不兼容可能会导致它无法正常运行。

请改用下面的代码。echo它做同样的事情，但每个快捷方式都在循环中使用调试命令显式编写。

counter=1
cd /my/image/directory
for f in $(ls -1)
do
  new_filename=$(printf "%04d" ${counter})     
  echo "renaming ${f} ..to.. ${new_filename}"
  mv ${f} ${new_filename}
  (( counter=${counter}+1 ))
done

屏幕输出会有点啰嗦。如果你有太多文件，你可能想| tee screen.out用命令添加到行尾done。这样您就可以回去查看screen.out中记录的哪个文件发生了什么。

Answer 2

我创建了自己的工具来执行此操作。它还维护文件扩展名，我没有提到，但可能应该包括在内。这是代码：

#!/bin/sh

dir=$1
cd $dir
echo "Renaming all files in $dir."
COUNTER=1
for i in `ls -1`
do
  extension=${i##*.}
  mv "$i" "$COUNTER.$extension"
  echo "$i ==> $COUNTER.$extension"
  COUNTER=$(expr $COUNTER + 1 )
done

它不（在撰写本文时）包括前导零，但它完成了工作。

Answer 3

尝试将文件夹中所有后缀为 .bash 的文件重命名为后缀为 .sh 很容易完成

rename .bash .sh *.bash

Answer 4

只要您不在乎哪个文件被重命名为什么，这很容易:)

counter=1
for f in *; do
    mv "$f" "$( printf "%04d" $((counter++)) )"
done