processing - How could I choose one particular file to load with loadStrings

Question

The title is explicit enough, I want to let the user choose the text file he want to open. I do not know if there is an explorer or an input field already implemented on processing.

Any help would be great.

Answer 1

使用选择输入。从处理参考：

打开特定于平台的文件选择器对话框以选择要输入的文件。选择完成后，选择的文件将被传递给“回调”函数。如果对话框关闭或取消，null 将被发送到函数，这样程序就不会等待额外的输入。由于线程的工作方式，回调是必要的。

我已经修改了他们在参考中提供的示例草图，以包括使用该loadStrings方法加载文件。

String[] txtFile;

void setup() {
  selectInput("Select a file to process:", "fileSelected");
}

void fileSelected(File selection) {
  if (selection == null) {
    println("Window was closed or the user hit cancel.");
  } else {
    String filepath = selection.getAbsolutePath();
    println("User selected " + filepath);
    // load file here
    txtFile = loadStrings(filepath);
  }
}

Answer 2

没有已实现的方法，但您可以像这样制作缓冲区并监视按键：

String[] File;
String keybuffer = "";
Char TriggerKey = Something;

void setup(){
  //do whatever here
}

void draw(){
  //Optional, to show the current buffer
  background(255);
  text(keybuffer,100,100);
}

void keyPressed(){
  if(keyCode >= 'a' && keyCode <= 'z'){
    keybuffer = keybuffer + key;
  }
  if(key == TriggerKey){
    File = loadStrings(keybuffer + ".txt");
  }
}

按下触发键时，它会加载文件