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为了需要进行群组分析，我正在尝试获取每个客户的下一步操作（取消订阅、升级、降级......）

我有一个包含以下数据的月度快照：

customer | month      | last_action   | last_action_date
1          01-01-2012   subscription    01-01-2012
1          02-01-2012   subscription    01-01-2012
1          03-01-2012   subscription    01-01-2012
1          04-01-2012   downgrade       04-01-2012
1          05-01-2012   downgrade       04-01-2012
1          06-01-2012   downgrade       04-01-2012
1          07-01-2012   unsubscription  07-01-2012

如您所见，该操作仅在完成的月份才知道，在 01-01-2012 月份我们还不知道客户在 2012 年 4 月 1 日降级，因此我们无法分析他的相对使用行为到他降级的月份。退订也是一样。

所需的数据集如下：

customer | month      | downgrade_date   | unsubscription_date
1          01-01-2012   04-01-2012         07-01-2012
1          02-01-2012   04-01-2012         07-01-2012
1          03-01-2012   04-01-2012         07-01-2012
1          04-01-2012   12-31-9999         07-01-2012
1          05-01-2012   12-31-9999         07-01-2012
1          06-01-2012   12-31-9999         07-01-2012
1          07-01-2012   12-31-9999         07-01-2012

我可以使用 last_value 分析函数轻松获得退订日期，但没有找到获取降级日期的方法。

这是我的 SQL 查询：

SELECT month_id, 
       customer_id,
       CASE 
         WHEN LAST_VALUE(last_action) OVER (PARTITION BY customer_id ORDER BY month_id RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) = 'unsubscription' THEN LAST_VALUE(last_action_date) OVER (PARTITION BY customer_id ORDER BY month_id RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)    
         ELSE TO_DATE('99991231', 'yyyymmdd')
       END unsubscription_date
FROM my_table
;

任何获取“下一个”行动日期的方法，例如“downgrade_date”。

我正在使用甲骨文。

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1 回答 1

1

在 oracle 11 中，您可以使用lead()以下ignore nulls选项执行此操作：

select customer, MONTH,
       lead(case when last_action = 'downgrade' then last_action_date end ignore nulls) over
                 (partition by customer order by month desc) as downgrade_date,
       lead(case when last_action = 'unsubscription' then last_action_date end ignore nulls) over
                 (partition by customer order by month desc) as downgrade_date,
from my_table t

如果你没有ignore nulls，你可以做类似的事情min()：

select customer, MONTH,
       min(case when last_action = 'downgrade' then last_action_date end) over
                (partition by customer order by month range between current and unbounded following
                ) as downgrade_date,
       min(case when last_action = 'unsubscription' then last_action_date end) over
                (partition by customer order by month range between current and unbounded following
                ) as unsubscription_date
from my_table t
于 2013-04-30T14:07:59.223 回答