2 
<?php
/*
 * Copyright 2011 Google Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
require_once '/google-api-php-client/src/Google_Client.php';
require_once '/google-api-php-client/src/contrib/Google_PlusService.php';

session_start();

$client = new Google_Client();
$client->setApplicationName("Google+ PHP Starter Application");
// Visit https://code.google.com/apis/console to generate your
// oauth2_client_id, oauth2_client_secret, and to register your oauth2_redirect_uri.
 $client->setClientId('');
 $client->setClientSecret('');
 $client->setRedirectUri('');
 $client->setDeveloperKey('');

$plus = new Google_PlusService($client);

if (isset($_REQUEST['logout'])) {
  unset($_SESSION['access_token']);
}

if (isset($_GET['code'])) {
  $client->authenticate($_GET['code']);
  $_SESSION['access_token'] = $client->getAccessToken();
  header('Location: http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF']);
}

if (isset($_SESSION['access_token'])) {
  $client->setAccessToken($_SESSION['access_token']);
}

if ($client->getAccessToken()) {
  $me = $plus->people->get('me');
  var_dump($me);

   // These fields are currently filtered through the PHP sanitize filters.
  // See http://www.php.net/manual/en/filter.filters.sanitize.php


  $url = filter_var($me['url'], FILTER_VALIDATE_URL);

  $img = filter_var($me['image']['url'], FILTER_VALIDATE_URL);

  $name = filter_var($me['displayName'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);

  $personMarkup = "<a rel='me' href='$url'>$name</a><div><img src='$img'></div>";

  $optParams = array('maxResults' => 100);
  $activities = $plus->activities->listActivities('me', 'public', $optParams);

  $activityMarkup = '';
  foreach($activities['items'] as $activity) {
    // These fields are currently filtered through the PHP sanitize filters.
    // See http://www.php.net/manual/en/filter.filters.sanitize.php
    $url = filter_var($activity['url'], FILTER_VALIDATE_URL);
    $title = filter_var($activity['title'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);
    $content = filter_var($activity['object']['content'], FILTER_SANITIZE_STRING, FILTER_FLAG_STRIP_HIGH);
    var_dump($content);
    exit;
    $activityMarkup .= "<div class='activity'><a href='$url'>$title</a><div>$content</div></div>";
  }


  // The access token may have been updated lazily.
  $_SESSION['access_token'] = $client->getAccessToken();
} else {
  $authUrl = $client->createAuthUrl();
}
?>
<!doctype html>
<html>
<head>
  <meta charset="utf-8">
  <link rel='stylesheet' href='style.css' />
</head>
<body>
<header><h1>Google+ Sample App</h1></header>
<div class="box">

<?php if(isset($personMarkup)): ?>
<div class="me"><?php print $personMarkup ?></div>
<?php endif ?>

<?php if(isset($activityMarkup)): ?>
<div class="activities">Your Activities: <?php print $activityMarkup ?></div>
<?php endif ?>

<?php
  if(isset($authUrl)) {
    print "<a class='login' href='$authUrl'>Connect Me!</a>";
  } else {
   print "<a class='logout' href='?logout'>Logout</a>";
  }
?>
</div>
</body>
</html>

我无法获取用户的电子邮件 ID 或生日。请给出建议以获取用户的电子邮件 ID 和生日。

4

1 回答 1

1

您的示例中有几处缺失的信息可能会影响您获得的结果。您可能希望从https://github.com/googleplus/gplus-quickstart-php上的快速入门应用开始，并专注于 index.html 中的登录按钮配置和 signin.php 中的 oauth 配置。

特别是，您需要确保在 index.html 页面中请求您需要的 oauth 范围。您没有在上面的示例中显示此部分，但要获取生日信息（假设用户已设置），您需要请求https://www.googleapis.com/auth/plus.login范围，要访问他们的电子邮件地址，您需要请求访问https://www.googleapis.com/auth/userinfo.email，然后从“tokeninfo”端点请求信息。有关更多信息，请参阅https://developers.google.com/+/api/oauth。

您展示的代码示例还显示了activity.get，而不是people.get 方法。您可能想发布说明确切问题的代码。但是，在这种情况下，请记住，如果此人未公开其生日，您将无法访问此字段。

于 2013-04-30T13:33:03.247 回答