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我在 windows phone 项目的三个不同堆栈面板中设计了三个按钮，即 button1、button2、button3。我已将 button1 的可见性属性设置为可见，即 visibilty="visible" 并将其余按钮可见性属性设置为折叠，因此在运行项目时，主页应该只显示 button1，我还完成了所有三个不同的编码按钮，例如单击按钮 1，按钮 2 应显示，单击按钮 2，按钮 3 应显示，这是代码..

private void button1_Click_1(object sender, RoutedEventArgs e)
{
    button1.Visibility = Visibility.Collapsed;
    stackPanel1.Visibility = Visibility.Visible;
}


    private void button2_Click(object sender, RoutedEventArgs e)
    {
        stackPanel1.Visibility = Visibility.Collapsed;
        stackPanel2.Visibility = Visibility.Visible;

    }

我想以这样的方式处理后退键按钮，当我单击按钮 1 时，按钮 2 应该显示，当我单击按钮 2 时，按钮 3 应该显示，现在如果我单击后退按钮（硬件），我应该移动到按钮 2，并且如果我再次点击后退键，我应该移动到 button1。我暂时遇到的情况是，当我在单击任何按钮后单击后退按钮时，应用程序已关闭，这是 Windows Phone 的默认行为。请帮帮我。这是我完整的 xamal 代码` 

<!--LayoutRoot is the root grid where all page content is placed-->
<Grid x:Name="LayoutRoot" Background="Transparent">
    <Grid.RowDefinitions>
        <RowDefinition Height="Auto"/>
        <RowDefinition Height="*"/>
    </Grid.RowDefinitions>

    <!--TitlePanel contains the name of the application and page title-->
    <StackPanel x:Name="TitlePanel" Grid.Row="0" Margin="12,17,0,28">
        <TextBlock x:Name="ApplicationTitle" Text="MY APPLICATION" Style="{StaticResource PhoneTextNormalStyle}"/>
        <TextBlock x:Name="PageTitle" Text="page name" Margin="9,-7,0,0" Style="{StaticResource PhoneTextTitle1Style}"/>
    </StackPanel>

    <!--ContentPanel - place additional content here-->
    <Grid x:Name="ContentPanel" Grid.Row="1" Margin="12,0,12,0">

        <StackPanel Height="244" HorizontalAlignment="Left" Margin="77,166,0,0" Name="stackPanel1" VerticalAlignment="Top" Width="316">
            <Button Content="Button1" Height="71" Name="button1" Width="160" Click="button1_Click" />
        </StackPanel>

        <StackPanel Height="247" HorizontalAlignment="Left" Margin="129,240,0,0" Name="stackPanel2" VerticalAlignment="Top" Width="267" Visibility="Collapsed">
            <Button Content="Button2" Height="71" Name="button2" Width="160" Click="button2_Click" />
        </StackPanel>



        <StackPanel Height="247" HorizontalAlignment="Left" Margin="129,240,0,0" Name="stackPanel3" VerticalAlignment="Top" Width="267" Visibility="Collapsed">
            <Button Content="Button3" Height="71" Name="button3" Width="160" Click="button3_Click" />
        </StackPanel>

    </Grid>
</Grid>

<!--Sample code showing usage of ApplicationBar-->
<!--<phone:PhoneApplicationPage.ApplicationBar>
    <shell:ApplicationBar IsVisible="True" IsMenuEnabled="True">
        <shell:ApplicationBarIconButton IconUri="/Images/appbar_button1.png" Text="Button 1"/>
        <shell:ApplicationBarIconButton IconUri="/Images/appbar_button2.png" Text="Button 2"/>
        <shell:ApplicationBar.MenuItems>
            <shell:ApplicationBarMenuItem Text="MenuItem 1"/>
            <shell:ApplicationBarMenuItem Text="MenuItem 2"/>
        </shell:ApplicationBar.MenuItems>
    </shell:ApplicationBar>
</phone:PhoneApplicationPage.ApplicationBar>-->

这是我的 .cs 代码：

 using System;
 using System.Collections.Generic;
 using System.Linq;
 using System.Net;   
 using System.Windows;
 using System.Windows.Controls;
 using System.Windows.Documents;
 using System.Windows.Input;
 using System.Windows.Media;
 using System.Windows.Media.Animation;
 using System.Windows.Shapes;
 using Microsoft.Phone.Controls;

  namespace backkeybehave
  {
    public partial class MainPage : PhoneApplicationPage
    {
    // Constructor
    public MainPage()
    {
        InitializeComponent();
    }



    private void button3_Click(object sender, RoutedEventArgs e)
    {


    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        stackPanel1.Visibility = Visibility.Collapsed;
        stackPanel2.Visibility = Visibility.Visible;
    }

    private void button2_Click(object sender, RoutedEventArgs e)
    {
        stackPanel2.Visibility = Visibility.Collapsed;
        stackPanel3.Visibility = Visibility.Visible;
    }


   }
 }
4

2 回答 2

1

不要那样做，返回键用于返回堆栈导航，而不是用于页面内导航。

另一方面，如果您真的想这样做，请查看PhoneApplicationPage.OnBackKeyPress并将其用于您的应用程序逻辑。

于 2013-04-30T11:55:09.993 回答
0

您需要实现自己的逻辑来跟踪覆盖 onbackkeypress 时应该发生的情况。

例如，如果在 button3 可见时按回应该始终显示 button2 您可以使用

if (button3.visibility == visibility.visible)
{
  button3.visibility = visibility.collapsed;
  button2.visibility = visibility.visible;
  e.cancel = true;
}

但这是您需要仔细考虑的事情，并包括所有可能的导航路径。

于 2013-05-01T14:15:23.190 回答