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我觉得有点愚蠢,但我无法让我的按钮在我的用户控件中触发。我已经使用按钮创建了用户控件,并在其背后的代码中添加了事件处理程序。此用户控件引用已添加到父级,并且在父页面上有此用户控件的实例。

当我单击该按钮时,它会返回上一页。我添加的断点没有被命中。这可能是我没有做的简单事情。

澳交所

    <h2>Notes</h2>

    <div id="divNoteForm">
        <h2>Create a new note</h2>
        <br />
        <table>
            <tr>
                <td>
                    <asp:Label ID="lblTitle" runat="server" Text="Title"></asp:Label>
                </td>
                <td>
                    <asp:TextBox ID="txtTitle" runat="server"></asp:TextBox>
                </td>
            </tr>
            <tr>
                <td>
                    <asp:Label ID="lblNoteText" runat="server" Text="Note"></asp:Label>
                </td>
                <td>
                    <asp:TextBox ID="txtNoteText" runat="server" Width="300" Rows="2"></asp:TextBox>
                </td>
            </tr>
          <tr>
                <td>

                    <asp:Button ID="btnSubmit" runat="server" Text="Submit note" OnClick="btnSubmit_Click"/>
              </td>
            </tr>
        </table>
    </div>

     <div id="divNoteGrid">
         <h2>Note Grid</h2>
         <br />
         <table>
             <tr>
                 <td>Date</td>
                 <td>Title</td>
                 <td>Description</td>
             </tr>
              <tr>
                 <td>22/04/2013</td>
                 <td>BSB</td>
                 <td>Phoned Amy Rowcliffe on 22/04/2013</td>
                 <td><u>Edit</u></td>
                   <td><u>Delete</u></td>
             </tr>
         </table>
         </div>


       <input type="radio" id="rdoForm" name="rdoNotes" style="width:10px" onchange="rdoChange(this)" value="Form" checked="checked">Show new note
    <input type="radio" id="rdoGrid"  name="rdoNotes" style="width:10px" onchange="rdoChange(this)" value="Grid">Show existing notes
</div>

<div id="NotesBtnForm" style="width: 500px; height: 40px; position: fixed; top: 0px; left:37%; border-style:solid; border-width:thin; z-index:10000;  opacity:1.0; background-color:white" >
    <asp:Button runat="server" ID="btnNotes" Text="Notes: 5" OnClientClick="showNotes();return false;" />
</div>

不会触发的按钮是 btnSubmit。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using Model.Company;
using Business;

public partial class WebControls_DataWebControls_NotesControl : System.Web.UI.UserControl
{

    CompanyNotesFactory companyNotesFormatter = new CompanyNotesFactory();
    List<CompanyNotesModel> results = new List<CompanyNotesModel>();

    protected void Page_Load(object sender, EventArgs e)
    {

    }

    public int NumToDisplay { get; set; }
    public string Notes { get; set; }
    protected string AdditionalInfo { get; private set; }

    //public override void DataBind()
    //{
    //    // Process the data we have been passed
    //    ProcessNotes(Notes);
    //    base.DataBind();
    //}

    public int NumNotes
    {
        get
        {
            return results.Count;
        }
    }

    //private void ProcessNotes(string Notes)
    //{
    //    if (string.IsNullOrEmpty(Notes))
    //    {
    //        AdditionalInfo = "No Additional Information Available";
    //        return;
    //    }

    //    results = companyNotesFormatter.GetCompanyNotes(Notes);

    //    if (NumToDisplay == 0)
    //        rptNotes.DataSource = results;
    //    else
    //        rptNotes.DataSource = results.Take(NumToDisplay);

    //    AdditionalInfo =  companyNotesFormatter.NotesLeadingText;

    //    rptNotes.DataBind();

    //} public void Add(string notesTitle, string notesText, Guid userID, int relatedID, string relatedType)

    //public event EventHandler btnSubmit_Click;

    protected void btnSubmit_Click(object sender, EventArgs e)
    {
        string test = Request["userid"];


        //Business.Core.Note.Add(txtTitle.Text, txtNoteText.Text, Request["userid"], );
    }

    }
4

2 回答 2

0

尝试用括号“()”调用函数。

于 2013-04-30T09:12:31.347 回答
0

我是对的,答案可能很明显。

按钮的默认回发行为是到不同的 URL。我正在为其开发的应用程序必须在某处进行一些配置,因为我以前使用过 asp.net 按钮,并且不必手动设置 URL。

谢谢您的帮助。

于 2013-04-30T11:02:14.657 回答