9

我正在使用此代码打开一个 excel 文件并将其保存在 DataGridView 中：

string name = "Items";
string constr = "Provider = Microsoft.Jet.OLEDB.4.0; Data Source=" + Dialog_Excel.FileName.ToString() + "; Extented Properties =\"Excel 8.0; HDR=Yes;\";";
OleDbConnection con = new OleDbConnection(constr);
OleDbDataAdapter sda = new OleDbDataAdapter("Select * From [" + name + "$]", con);
DataTable data = new DataTable();
sda.Fill(data);
grid_items.DataSource = data;

如上所述： 此 youtube 链接

但我收到一个 ISAM 错误。有什么建议吗？

4

5 回答 5

34

我发布了 Excel 2003 和 Excel 2007+ 的解决方案。

你错过'了Extended Properties

对于Excel 2003试试这个

    private void button1_Click(object sender, EventArgs e)
    {
        String name = "Items";
        String constr = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" +
                        "C:\\Sample.xls" + 
                        ";Extended Properties='Excel 8.0;HDR=YES;';";

        OleDbConnection con = new OleDbConnection(constr);
        OleDbCommand oconn = new OleDbCommand("Select * From [" + name + "$]", con);
        con.Open();

        OleDbDataAdapter sda = new OleDbDataAdapter(oconn);
        DataTable data = new DataTable();
        sda.Fill(data);
        grid_items.DataSource = data;
    }

顺便说一句，我很久以前就停止与 Jet 合作了。我现在使用 ACE。

    private void button1_Click(object sender, EventArgs e)
    {
        String name = "Items";
        String constr = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" +
                        "C:\\Sample.xls" + 
                        ";Extended Properties='Excel 8.0;HDR=YES;';";

        OleDbConnection con = new OleDbConnection(constr);
        OleDbCommand oconn = new OleDbCommand("Select * From [" + name + "$]", con);
        con.Open();

        OleDbDataAdapter sda = new OleDbDataAdapter(oconn);
        DataTable data = new DataTable();
        sda.Fill(data);
        grid_items.DataSource = data;
    }

在此处输入图像描述

对于Excel 2007+

    private void button1_Click(object sender, EventArgs e)
    {
        String name = "Items";
        String constr = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" +
                        "C:\\Sample.xlsx" + 
                        ";Extended Properties='Excel 12.0 XML;HDR=YES;';";

        OleDbConnection con = new OleDbConnection(constr);
        OleDbCommand oconn = new OleDbCommand("Select * From [" + name + "$]", con);
        con.Open();

        OleDbDataAdapter sda = new OleDbDataAdapter(oconn);
        DataTable data = new DataTable();
        sda.Fill(data);
        grid_items.DataSource = data;
    }
于 2013-04-30T09:06:43.427 回答
5

我使用了以下代码，它正在工作！

using System.Data.OleDb;
using System.IO;
using System.Text.RegularExpressions;

private void btopen_Click(object sender, EventArgs e)
{
   try
   {
     OpenFileDialog openFileDialog1 = new OpenFileDialog();  //create openfileDialog Object
     openFileDialog1.Filter = "XML Files (*.xml; *.xls; *.xlsx; *.xlsm; *.xlsb) |*.xml; *.xls; *.xlsx; *.xlsm; *.xlsb";//open file format define Excel Files(.xls)|*.xls| Excel Files(.xlsx)|*.xlsx| 
     openFileDialog1.FilterIndex = 3;

     openFileDialog1.Multiselect = false;        //not allow multiline selection at the file selection level
     openFileDialog1.Title = "Open Text File-R13";   //define the name of openfileDialog
     openFileDialog1.InitialDirectory = @"Desktop"; //define the initial directory

     if (openFileDialog1.ShowDialog() == DialogResult.OK)        //executing when file open
     {
       string pathName = openFileDialog1.FileName;
       fileName = System.IO.Path.GetFileNameWithoutExtension(openFileDialog1.FileName);
       DataTable tbContainer = new DataTable();
       string strConn = string.Empty;
       string sheetName = fileName;

       FileInfo file = new FileInfo(pathName);
       if (!file.Exists) { throw new Exception("Error, file doesn't exists!"); }
       string extension = file.Extension;
       switch (extension)
       {
          case ".xls":
                   strConn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + pathName + ";Extended Properties='Excel 8.0;HDR=Yes;IMEX=1;'";
                   break;
          case ".xlsx":
                   strConn = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + pathName + ";Extended Properties='Excel 12.0;HDR=Yes;IMEX=1;'";
                   break;
          default:
                   strConn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + pathName + ";Extended Properties='Excel 8.0;HDR=Yes;IMEX=1;'";
                   break;
         }
         OleDbConnection cnnxls = new OleDbConnection(strConn);
         OleDbDataAdapter oda = new OleDbDataAdapter(string.Format("select * from [{0}$]", sheetName), cnnxls);
         oda.Fill(tbContainer);

         dtGrid.DataSource = tbContainer;
       }

     }
     catch (Exception)
     {
        MessageBox.Show("Error!");
     }
  }
于 2017-03-23T07:24:40.203 回答
1

试试下面的代码片段，它工作正常。

private void button1_Click(object sender, EventArgs e)
{
     try
     {
             OpenFileDialog openfile1 = new OpenFileDialog();
             if (openfile1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
             {
                   this.textBox1.Text = openfile1.FileName;
             }
             {
                   string pathconn = "Provider = Microsoft.jet.OLEDB.4.0; Data source=" + textBox1.Text + ";Extended Properties=\"Excel 8.0;HDR= yes;\";";
                   OleDbConnection conn = new OleDbConnection(pathconn);
                   OleDbDataAdapter MyDataAdapter = new OleDbDataAdapter("Select * from [" + textBox2.Text + "$]", conn);
                   DataTable dt = new DataTable();
                   MyDataAdapter.Fill(dt);
                   dataGridView1.DataSource = dt;
             }
      }
      catch { }
}
于 2013-10-25T06:56:50.497 回答
0

试试下面的程序

using System;
using System.Data;
using System.Windows.Forms;
using System.Data.SqlClient;

namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        System.Data.OleDb.OleDbConnection MyConnection;
        System.Data.DataSet DtSet;
        System.Data.OleDb.OleDbDataAdapter MyCommand;
        MyConnection = new System.Data.OleDb.OleDbConnection(@"provider=Microsoft.Jet.OLEDB.4.0;Data Source='c:\csharp.net-informations.xls';Extended Properties=Excel 8.0;");
        MyCommand = new System.Data.OleDb.OleDbDataAdapter("select * from [Sheet1$]", MyConnection);
        MyCommand.TableMappings.Add("Table", "Net-informations.com");
        DtSet = new System.Data.DataSet();
        MyCommand.Fill(DtSet);
        dataGridView1.DataSource = DtSet.Tables[0];
        MyConnection.Close();
    }
}
}
于 2014-07-31T11:44:06.033 回答
0

就我而言，我使用 Microsoft.Office.Interop.Excel 加载 excel 文件。我保存在数据表中以便在我的项目中重复使用，而无需再次从 datagridview 重新加载数据。

 using Excel = Microsoft.Office.Interop.Excel;
 Excel.Application excelApp = new Excel.Application();
 public void LoadDataGridView(DataGridView dataGridView, DataTable dataTable)
    {
        if (excelApp != null)
        {
            Excel.Workbook excelWorkbook = excelApp.Workbooks.Open(parentPath + @"\test.xlsx", 0, true, 5, "", "", true, Excel.XlPlatform.xlWindows, "\t", false, false, 0, true, 1, 0);
            Excel.Worksheet excelWorksheet = (Excel.Worksheet)excelWorkbook.Sheets[1];

            Excel.Range excelRange = excelWorksheet.UsedRange;
            int rowCount = excelRange.Rows.Count;
            int colCount = excelRange.Columns.Count;
            DataRow row = null;
            for (int i = 1; i <= rowCount; i++)
            {
                if (i != 1)
                    row = dataTable.NewRow();
                for (int j = 1; j <= colCount; j++)
                {
                    if (i == 1)
                        dataTable.Columns.Add(excelRange.Cells[1, j].value);
                    else
                    {
                        if(!String.IsNullOrEmpty(excelRange.Cells[i, 1].value2.ToString()))
                        {
                            row[j - 1] = excelRange.Cells[i, j].value;
                        }
                    }
                }
                if (row != null && !String.IsNullOrEmpty(row[@"Id"].ToString()))
                    dataTable.Rows.Add(row);
            }
            dataGridView.DataSource = dataTable;
            excelWorkbook.Close();
            excelApp.Quit();
        }
    }
于 2021-06-17T16:10:47.097 回答