1

日期表：

id  start_date  end_date
1   2013-04-28  2013-04-29
3   2013-04-18  2013-04-25
4   2013-05-22  2013-04-30
5   2013-05-02  2013-04-30
6   2013-04-29  2013-04-30

时间表：

id  start_time  end_time
1   11:00 AM    12:00 AM
2   12:00 PM    03:00 PM

应用表：

id  app_name
1   Test
2   Test1

表的关系存储在相关表中：

app_id  date_id  time_id
1          1       1 
1          1       2 
2          1       2

我触发了一个 sql 查询以从数据库中获取数据：

SELECT app.id as id,app.app_name,date.id as date_id ,
                date.start_date,date.end_date,time.id as time_id,time.start_time,time.end_time as end_time
                FROM  related_data
                INNER JOIN app ON app.id = app_id
                INNER JOIN DATE ON date.id = date_id
                INNER JOIN Time ON time.id = time_id
                LIMIT 0 , 30

但它返回：

id  app_name    date_id     start_date  end_date    time_id     start_time  end_time
1   Test    1   2013-04-28  2013-04-29  1   11:00 AM    12:00 AM
1   Test    1   2013-04-28  2013-04-29  2   12:00 PM    03:00 PM
2   Test1   1   2013-04-28  2013-04-29  2   12:00 PM    03:00 PM

但我想要这样：

id  app_name    date_id     start_date  end_date    time_id     start_time  end_time
1   Test    1   2013-04-28  2013-04-29  1,2     11:00 AM,12:00PM    12:00 AM,03:00PM
2   Test1   1   2013-04-28  2013-04-29  2   12:00 PM    03:00 PM

如果应用程序 ID 相同且日期 ID 或时间 ID 不同，则连接数据。

4

1 回答 1

1

利用GROUP_CONCAT

SELECT  app.id as id,
        app.app_name,
        date.id as date_id , 
        date.start_date,
        date.end_date,
        GROUP_CONCAT(time.id) as time_id,
        GROUP_CONCAT(time.start_time) start_time,
        GROUP_CONCAT(time.end_time) as end_time 
FROM    related_data 
        INNER JOIN app 
            ON app.id = app_id 
        INNER JOIN DATE 
            ON date.id = date_id 
        INNER JOIN Time 
            ON time.id = time_id 
GROUP   BY  app.id as id,
            app.app_name,
            date.id as date_id , 
            date.start_date,
            date.end_date
LIMIT   0, 30
于 2013-04-30T05:52:59.717 回答