90

我对Spring和 Spring 安全性比较陌生。

我试图编写一个程序，我需要在服务器端使用 Spring 安全性对用户进行身份验证，

我想出了以下内容：

public class CustomAuthenticationProvider extends AbstractUserDetailsAuthenticationProvider{
    @Override
    protected void additionalAuthenticationChecks(UserDetails userDetails, UsernamePasswordAuthenticationToken usernamePasswordAuthenticationToken)
                    throws AuthenticationException
    {
        System.out.println("Method invoked : additionalAuthenticationChecks isAuthenticated ? :"+usernamePasswordAuthenticationToken.isAuthenticated());
    }

    @Override
    protected UserDetails retrieveUser(String username,UsernamePasswordAuthenticationToken authentication) throws AuthenticationException 
    {
        System.out.println("Method invoked : retrieveUser");
        //so far so good, i can authenticate user here, and throw exception if not authenticated!!
        //THIS IS WHERE I WANT TO ACCESS SESSION OBJECT
    }
}

我的用例是，当用户通过身份验证时，我需要放置一个属性，例如：

session.setAttribute("userObject", myUserObject);

myUserObject 是某个类的对象，我可以跨多个用户请求在整个服务器代码中访问它。

4

8 回答 8

155

你的朋友在这里org.springframework.web.context.request.RequestContextHolder

// example usage
public static HttpSession session() {
    ServletRequestAttributes attr = (ServletRequestAttributes) RequestContextHolder.currentRequestAttributes();
    return attr.getRequest().getSession(true); // true == allow create
}

这将由标准的 spring mvc dispatch servlet 填充，但是如果您使用不同的 Web 框架，您可以org.springframework.web.filter.RequestContextFilter在您的管理器中添加一个过滤器web.xml来管理持有者。

编辑：作为一个附带问题，您实际上要做什么，我不确定您是否需要访问aHttpSession的retieveUser方法UserDetailsService。Spring security 会以任何方式将 UserDetails 对象放入会话中。它可以通过访问来检索SecurityContextHolder：

public static UserDetails currentUserDetails(){
    SecurityContext securityContext = SecurityContextHolder.getContext();
    Authentication authentication = securityContext.getAuthentication();
    if (authentication != null) {
        Object principal = authentication.getPrincipal();
        return principal instanceof UserDetails ? (UserDetails) principal : null;
    }
    return null;
}
于 2009-10-27T07:32:40.813 回答
34

由于您使用的是 Spring，请坚持使用 Spring，不要像其他帖子那样自己破解它。

Spring手册说：

出于安全目的，您不应直接与 HttpSession 交互。这样做根本没有理由 - 始终使用 SecurityContextHolder 代替。

访问会话的建议最佳实践是：

Object principal = SecurityContextHolder.getContext().getAuthentication().getPrincipal();

if (principal instanceof UserDetails) {
  String username = ((UserDetails)principal).getUsername();
} else {
  String username = principal.toString();
}

这里的关键是 Spring 和 Spring Security 为您做了各种很棒的事情，比如 Session Fixation Prevention。这些事情假设您正在使用设计为使用的 Spring 框架。因此，在您的 servlet 中，使其具有上下文感知能力并像上面的示例一样访问会话。

如果您只需要在会话范围内存储一些数据，请尝试像这个示例一样创建一些会话范围的 bean ，并让 autowire 发挥它的魔力。:)

于 2012-10-17T19:13:24.607 回答
6

我做了我自己的工具。它很方便。:)

package samples.utils;

import java.util.Arrays;
import java.util.Collection;
import java.util.Locale;

import javax.servlet.ServletContext;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpSession;
import javax.sql.DataSource;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.NoSuchBeanDefinitionException;
import org.springframework.beans.factory.NoUniqueBeanDefinitionException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationEventPublisher;
import org.springframework.context.MessageSource;
import org.springframework.core.convert.ConversionService;
import org.springframework.core.io.ResourceLoader;
import org.springframework.core.io.support.ResourcePatternResolver;
import org.springframework.ui.context.Theme;
import org.springframework.util.ClassUtils;
import org.springframework.web.context.request.RequestContextHolder;
import org.springframework.web.context.request.ServletRequestAttributes;
import org.springframework.web.context.support.WebApplicationContextUtils;
import org.springframework.web.servlet.LocaleResolver;
import org.springframework.web.servlet.ThemeResolver;
import org.springframework.web.servlet.support.RequestContextUtils;


/**
 * SpringMVC通用工具
 * 
 * @author 应卓(yingzhor@gmail.com)
 *
 */
public final class WebContextHolder {

    private static final Logger LOGGER = LoggerFactory.getLogger(WebContextHolder.class);

    private static WebContextHolder INSTANCE = new WebContextHolder();

    public WebContextHolder get() {
        return INSTANCE;
    }

    private WebContextHolder() {
        super();
    }

    // --------------------------------------------------------------------------------------------------------------

    public HttpServletRequest getRequest() {
        ServletRequestAttributes attributes = (ServletRequestAttributes) RequestContextHolder.currentRequestAttributes();
        return attributes.getRequest();
    }

    public HttpSession getSession() {
        return getSession(true);
    }

    public HttpSession getSession(boolean create) {
        return getRequest().getSession(create);
    }

    public String getSessionId() {
        return getSession().getId();
    }

    public ServletContext getServletContext() {
        return getSession().getServletContext();    // servlet2.3
    }

    public Locale getLocale() {
        return RequestContextUtils.getLocale(getRequest());
    }

    public Theme getTheme() {
        return RequestContextUtils.getTheme(getRequest());
    }

    public ApplicationContext getApplicationContext() {
        return WebApplicationContextUtils.getWebApplicationContext(getServletContext());
    }

    public ApplicationEventPublisher getApplicationEventPublisher() {
        return (ApplicationEventPublisher) getApplicationContext();
    }

    public LocaleResolver getLocaleResolver() {
        return RequestContextUtils.getLocaleResolver(getRequest());
    }

    public ThemeResolver getThemeResolver() {
        return RequestContextUtils.getThemeResolver(getRequest());
    }

    public ResourceLoader getResourceLoader() {
        return (ResourceLoader) getApplicationContext();
    }

    public ResourcePatternResolver getResourcePatternResolver() {
        return (ResourcePatternResolver) getApplicationContext();
    }

    public MessageSource getMessageSource() {
        return (MessageSource) getApplicationContext();
    }

    public ConversionService getConversionService() {
        return getBeanFromApplicationContext(ConversionService.class);
    }

    public DataSource getDataSource() {
        return getBeanFromApplicationContext(DataSource.class);
    }

    public Collection<String> getActiveProfiles() {
        return Arrays.asList(getApplicationContext().getEnvironment().getActiveProfiles());
    }

    public ClassLoader getBeanClassLoader() {
        return ClassUtils.getDefaultClassLoader();
    }

    private <T> T getBeanFromApplicationContext(Class<T> requiredType) {
        try {
            return getApplicationContext().getBean(requiredType);
        } catch (NoUniqueBeanDefinitionException e) {
            LOGGER.error(e.getMessage(), e);
            throw e;
        } catch (NoSuchBeanDefinitionException e) {
            LOGGER.warn(e.getMessage());
            return null;
        }
    }

}
于 2014-02-28T06:34:56.793 回答
4

事实上，即使会话在 HttpSessionLisener 上被销毁，您也可以通过执行以下操作访问会话中的信息：

public void sessionDestroyed(HttpSessionEvent hse) {
    SecurityContextImpl sci = (SecurityContextImpl) hse.getSession().getAttribute("SPRING_SECURITY_CONTEXT");
    // be sure to check is not null since for users who just get into the home page but never get authenticated it will be
    if (sci != null) {
        UserDetails cud = (UserDetails) sci.getAuthentication().getPrincipal();
        // do whatever you need here with the UserDetails
    }
 }

或者您也可以在任何有 HttpSession 对象可用的地方访问信息，例如：

SecurityContextImpl sci = (SecurityContextImpl) session().getAttribute("SPRING_SECURITY_CONTEXT");

最后一个假设你有类似的东西：

HttpSession sesssion = ...; // can come from request.getSession(false);
于 2013-04-25T17:40:17.777 回答
2

我尝试使用下一个代码并且工作出色

    import org.springframework.security.core.Authentication;
    import org.springframework.security.core.context.SecurityContextHolder;
    import org.springframework.stereotype.Controller;
    import org.springframework.ui.ModelMap;
    import org.springframework.web.bind.annotation.RequestMapping;
    import org.springframework.web.bind.annotation.RequestMethod;

    /**
     * Created by jaime on 14/01/15.
     */

    @Controller
    public class obteinUserSession {
        @RequestMapping(value = "/loginds", method = RequestMethod.GET)
        public String UserSession(ModelMap modelMap) {
            Authentication auth = SecurityContextHolder.getContext().getAuthentication();
            String name = auth.getName();
            modelMap.addAttribute("username", name);
            return "hellos " + name;
        }
于 2015-01-14T21:14:02.953 回答
2

如果您需要的只是用户的详细信息，对于Spring 4.x 版，您可以使用Spring 提供@AuthenticationPrincipal的@EnableWebSecurity标签，如下所示。

安全配置类：

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
   ...
}

控制器方法：

@RequestMapping("/messages/inbox")
public ModelAndView findMessagesForUser(@AuthenticationPrincipal User user) {
    ...
}
于 2017-09-24T15:13:50.843 回答
2

在我的场景中，我已经像这样将 HttpSession 注入到 CustomAuthenticationProvider 类中

public class CustomAuthenticationProvider extends  AbstractUserDetailsAuthenticationProvider{

    @Autowired 
    private HttpSession httpSession;

    @Override
    protected void additionalAuthenticationChecks(UserDetails userDetails, UsernamePasswordAuthenticationToken usernamePasswordAuthenticationToken)
             throws AuthenticationException
    {
        System.out.println("Method invoked : additionalAuthenticationChecks isAuthenticated ? :"+usernamePasswordAuthenticationToken.isAuthenticated());
    }

    @Override
    protected UserDetails retrieveUser(String username,UsernamePasswordAuthenticationToken authentication) throws AuthenticationException 
    {
        System.out.println("Method invoked : retrieveUser");
        //so far so good, i can authenticate user here, and throw exception 
if not authenticated!!
        //THIS IS WHERE I WANT TO ACCESS SESSION OBJECT
        httpSession.setAttribute("userObject", myUserObject);
    }
}
于 2019-04-04T20:17:38.947 回答
0 
ServletRequestAttributes attr = (ServletRequestAttributes) RequestContextHolder.currentRequestAttributes();
attr.getSessionId();
于 2019-05-11T10:46:28.267 回答