该解决方案基于Jonathan 的代码 here。如果你想上传一个大文件，比如 1GB 的视频文件，你必须把文件夹起来并通过几个请求发送（一个请求会超时）。首先，您在Web.config中设置客户端和服务器端的最大限制，如其他答案中所述。
<system.webServer>
<security>
<requestFiltering>
<requestLimits maxAllowedContentLength="2147483647" />
</requestFiltering>
</security>
<system.webServer>
和
<system.web>
<httpRuntime targetFramework="4.5" maxRequestLength="2147483647" />
</system.web>
然后分块文件，并发送每个卡盘，等待响应并发送下一个块。这是 html（VideoDiv用作上传面板）、javascript (jQuery) 和控制器代码。
<div id="VideoDiv">
<label>Filename:</label>
<input type="file" id="fileInput" /><br/><br/>
<input type="button" id="btnUpload" value="Upload a presentation"/><br/><br/>
<div id="progressbar_container" style="width: 100%; height: 30px; position: relative; background-color: grey; display: none">
<div id="progressbar" style="width: 0%; height: 100%; position: absolute; background-color: green"></div>
<span id="progressbar_label" style="position: absolute; left: 35%; top: 20%">Uploading...</span>
</div>
</div>
用于卡盘、调用控制器和更新进度条的 Javascript 代码：
var progressBarStart = function() {
$("#progressbar_container").show();
}
var progressBarUpdate = function (percentage) {
$('#progressbar_label').html(percentage + "%");
$("#progressbar").width(percentage + "%");
}
var progressBarComplete = function() {
$("#progressbar_container").fadeOut(500);
}
var file;
$('#fileInput').change(function(e) {
file = e.target.files[0];
});
var uploadCompleted = function() {
var formData = new FormData();
formData.append('fileName', file.name);
formData.append('completed', true);
var xhr2 = new XMLHttpRequest();
xhr2.onload = function() {
progressBarUpdate(100);
progressBarComplete();
}
xhr2.open("POST", "/Upload/UploadComplete?fileName=" + file.name + "&complete=" + 1, true);
xhr2.send(formData);
}
var multiUpload = function(count, counter, blob, completed, start, end, bytesPerChunk) {
counter = counter + 1;
if (counter <= count) {
var chunk = blob.slice(start, end);
var xhr = new XMLHttpRequest();
xhr.onload = function() {
start = end;
end = start + bytesPerChunk;
if (count == counter) {
uploadCompleted();
} else {
var percentage = (counter / count) * 100;
progressBarUpdate(percentage);
multiUpload(count, counter, blob, completed, start, end, bytesPerChunk);
}
}
xhr.open("POST", "/Upload/MultiUpload?id=" + counter.toString() + "&fileName=" + file.name, true);
xhr.send(chunk);
}
}
$("#VideoDiv").on("click", "#btnUpload", function() {
var blob = file;
var bytesPerChunk = 3757000;
var size = blob.size;
var start = 0;
var end = bytesPerChunk;
var completed = 0;
var count = size % bytesPerChunk == 0 ? size / bytesPerChunk : Math.floor(size / bytesPerChunk) + 1;
var counter = 0;
progressBarStart();
multiUpload(count, counter, blob, completed, start, end, bytesPerChunk);
});
这是将 chucnk 存储在（“App_Data/Videos/Temp”）中的上传控制器，然后将它们合并并存储在（“App_Data/Videos”）中：
public class UploadController : Controller
{
private string videoAddress = "~/App_Data/Videos";
[HttpPost]
public string MultiUpload(string id, string fileName)
{
var chunkNumber = id;
var chunks = Request.InputStream;
string path = Server.MapPath(videoAddress+"/Temp");
string newpath = Path.Combine(path, fileName+chunkNumber);
using (FileStream fs = System.IO.File.Create(newpath))
{
byte[] bytes = new byte[3757000];
int bytesRead;
while ((bytesRead=Request.InputStream.Read(bytes,0,bytes.Length))>0)
{
fs.Write(bytes,0,bytesRead);
}
}
return "done";
}
[HttpPost]
public string UploadComplete(string fileName, string complete)
{
string tempPath = Server.MapPath(videoAddress + "/Temp");
string videoPath = Server.MapPath(videoAddress);
string newPath = Path.Combine(tempPath, fileName);
if (complete=="1")
{
string[] filePaths = Directory.GetFiles(tempPath).Where(p=>p.Contains(fileName)).OrderBy(p => Int32.Parse(p.Replace(fileName, "$").Split('$')[1])).ToArray();
foreach (string filePath in filePaths)
{
MergeFiles(newPath, filePath);
}
}
System.IO.File.Move(Path.Combine(tempPath, fileName),Path.Combine(videoPath,fileName));
return "success";
}
private static void MergeFiles(string file1, string file2)
{
FileStream fs1 = null;
FileStream fs2 = null;
try
{
fs1 = System.IO.File.Open(file1, FileMode.Append);
fs2 = System.IO.File.Open(file2, FileMode.Open);
byte[] fs2Content = new byte[fs2.Length];
fs2.Read(fs2Content, 0, (int) fs2.Length);
fs1.Write(fs2Content, 0, (int) fs2.Length);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message + " : " + ex.StackTrace);
}
finally
{
if (fs1 != null) fs1.Close();
if (fs2 != null) fs2.Close();
System.IO.File.Delete(file2);
}
}
}
但是，如果两个用户同时上传同名的文件，就会出现一些问题，你必须处理这个问题。通过阅读responseText，您可以捕捉到一些错误和异常并对其进行修整。