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我在一个对象中有一个包含 12 个类别的列表,我想获取该列表的前 3 个条目,并且只显示这 3 个条目中每一个的数据库的最后一个条目。我究竟做错了什么?我不能只接受 3 个特定类别的最后一个条目......

这是我的 app.py (不工作!):

# try and get experiences where mood_name is inside the mood list
try:
    experiences = models.Experience.objects(mood=mood_name)

except:
    abort(404)

# get the first 3 interests inside Experience
ints = models.Experience.objects.fields(slice__interest=[0,2])

interest = ()

for i in ints:

    interest = 'i'
    # get the last experience of a specific interest
    exp_highlight = models.Experience.objects(interest=interest).order_by('-timestamp')

这是我的 HTML/Jinja(不工作):

{% for experience in experiences if experience.mood == 'Chill' %}
          {% if loop.index <= 2 %}

          <div class="item">
            <img class="image-highlight" src="https://s3.amazonaws.com/aliceapp/{{experience.filename}}"/>

              <div id="purple-small-box">
                <h6>{{ experience.interest }}</h6>
              </div>

                <div class="small-boxes">
                  <h3>{{ experience.title }}</h3>
                  <p>{{ experience.description }}</p>
                </div>
          </div>

          {% endif %}
      {% endfor %}   
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1 回答 1

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我认为问题出在这一行:

interest = 'i'

你可能想要类似的东西

interest = str(i)

甚至

interest = i

否则,您的查找将查找兴趣为“i”而不是某个数字的对象。

于 2013-04-29T16:45:56.433 回答