嗨,我遇到了这个错误,我似乎看不到问题,所以任何想法,一套新的眼睛可能会有所帮助。
完全错误:
您的 SQL 语法有错误;检查与您的 MySQL 服务器版本相对应的手册,以在第 1 行的 'desc='ittititi', price='22', img='img.png'' 附近使用正确的语法
<?php
// Include MySQL class
require_once('../inc/mysql.php');
// Include database connection
require_once('../inc/global.inc.php');
// Include functions
require_once('../inc/functions.inc.php');
// Start the session
session_start();
?>
<?php
// try to create a new record from the submission
$genre = mysql_real_escape_string($_REQUEST['genre']);
$title = mysql_real_escape_string($_REQUEST['title']);
$desc = mysql_real_escape_string($_REQUEST['desc']);
$price = mysql_real_escape_string($_REQUEST['price']);
$img= mysql_real_escape_string($_REQUEST['img']);
if (!empty($genre) && !empty($title) && !empty($desc) && !empty($price) && !empty($img)) {
// here we define the SQL command
$query = "SELECT * FROM books WHERE title='$title'";
// submit the query to the database
$res=mysql_query($query);
// make sure it worked!
if (!$res) {
mysql_error();
exit;
}
// find out how many records we got
$num = mysql_numrows($res);
if ($num>0) {
echo "<h3>That book title is already taken</h3>\n";
exit;
}
// Create the record
$query = "INSERT INTO books SET genre='$genre', title='$title', desc='$desc', price='$price', img='$img'";
$res = mysql_query($query)or die(mysql_error());
if (! $res) {
echo mysql_error();
exit;
} else {
echo "<h3>Book Created</h3>\n";
echo $_SESSION['title']=$title;
}
}
?>
<form name="newbook" method="post">
<table border=0>
<tr>
<td>Genre:</td>
<td><input type=text name='genre'></td>
</tr>
<tr>
<td>Title:</td>
<td><input type=text name='title'></td>
</tr>
<tr>
<td>Description:</td>
<td><input type=text name='desc'></td>
</tr>
<tr>
<td>Price:</td>
<td><input type=number name='price'></td>
</tr>
<tr>
<td>Image:</td>
<td><input type=text name='img'></td>
</tr>
<tr>
<td colspan=2>
<input type=submit value="Create my account">
</td>
</tr>
</table>
</form>