我有四个下拉框,它们显示来自数据库的信息,但它只显示四个中的两个。 http://www.cupboard2stomach.com/php/get.php?dropdown1=bread&dropdown3=chicken&Submit=Submit这是它目前的样子。
我的代码有问题吗?
Ingredient 1:<select name= "dropdown1" id = "drop1"/>
<?php
while ($line = mysql_fetch_array($result1, MYSQL_ASSOC)) {
?>
<option value="<?php echo $line['ingredientname'];?>"> <?php echo $line['ingredientname'];?> </option>
<?php
}
?>
Ingredient 2:<select name = "dropdown2" id = "drop2"/>
<?php
while ($line = mysql_fetch_array($result2, MYSQL_ASSOC)) {
?>
<option value="<?php echo $line['ingredientname'];?>"> <?php echo $line['ingredientname'];?> </option>
<?php
}
?>
Ingredient 3:<select name = "dropdown3" id = "drop3"/>
<?php
while ($line = mysql_fetch_array($result3, MYSQL_ASSOC)) {
?>
<option value="<?php echo $line['ingredientname'];?>"> <?php echo $line['ingredientname'];?> </option>
<?php
}
?>
Ingredient 4:<select name = "dropdown4" id = "drop4"/>
<?php
while ($line = mysql_fetch_array($result4, MYSQL_ASSOC)) {
?>
<option value="<?php echo $line['ingredientname'];?>"> <?php echo $line['ingredientname'];?> </option>
<?php
}
?>