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我希望我的网址是这样的：www.app.com/projects/projectnumber
但是从我在文档中阅读的内容来看，我需要指定三个段来发送参数？
所以我得到了www.app.com/projects/index/projectnumber。无论如何我可以只用两个段来做到这一点，这样我就可以摆脱“索引”？
你可以试试这个
$route['projects/(:num)'] = "projects/index/$1";
https://www.codeigniter.com/user_guide/general/routing.html