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我正在尝试从数据库中获取值并在列表视图中显示所有值。我的代码是：

try
    {           
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://10.0.2.2/meetingschedular/viewdetail.php?mdate="+viewdate.getText().toString());
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
        }
        catch(Exception e)
        {
            Toast.makeText(getBaseContext(),e.toString() ,Toast.LENGTH_LONG).show();
        }

        //Convert response to string
        try
        {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"));
            sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null)
                {
                    sb.append(line + "\n");
                }
                is.close();
                result = sb.toString();                 
        }
        catch(Exception e)
        {
            Toast.makeText(getBaseContext(),e.toString() ,Toast.LENGTH_LONG).show();
        }
        //END Convert response to string

            try
            {               
                JSONArray jArray =  new JSONArray(result);

                for(int i=0;i<jArray.length();i++)
                {   
                    JSONArray innerJsonArray = jArray.getJSONArray(i);
                    JSONObject json_data = innerJsonArray.getJSONObject(0);                     
                    String at= json_data.getString("attendees"); 
                    String at1=json_data.getString("title");                    
                    String at2=json_data.getString("mtime");
                    String at3=json_data.getString("venue");
                    s.append(j+"Attendees:"+at);
                    s.append("\nTitle:"+at1);
                    s.append("\nTime:"+at2);
                    s1.append("\nVenue:"+at3);

                    r.add(s.toString());
                    //r.add(s1.toString());
                    j++;
                }

                l.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_expandable_list_item_1, r));

            }

            catch(Exception e1)
            {
                e1.printStackTrace();
                Toast.makeText(getBaseContext(),"Sorry No Meeting Details",Toast.LENGTH_LONG).show();
            }

但是当我显示列表视图时，我只从数据库中获取一行，并且它显示了两次，而数据库的第二行没有显示。

像这样

请帮帮我.. :(

这是我的 XML 文件

'<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/prle"
android:orientation="vertical"
tools:context=".Meetdetail1Activity" >

<TextView
    android:id="@+id/textView1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentLeft="true"
    android:layout_alignParentTop="true"
    android:background="@color/Grey"
    android:text="@string/homelinkpropose"
    android:textColor="@color/blue" />

<TextView
    android:id="@+id/textView2"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentRight="true"
    android:layout_alignParentTop="true"
    android:background="@color/Grey"
    android:text="@string/logoutproposemeet"
    android:textColor="@color/blue" />

<TextView
    android:id="@+id/textView3"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_below="@+id/textView1"
    android:layout_centerHorizontal="true"
    android:layout_marginTop="15dp"
    android:text="@string/meetdetaill"
    android:textColor="@color/yellow"
    android:textSize="@dimen/meetdettextsize" />

<TextView
    android:id="@+id/textView4"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_below="@+id/textView3"
    android:layout_centerHorizontal="true"
    android:text="@string/viewdate" />

<ListView
    style="@style/dividedListStyle"
    android:id="@+id/listview"
    android:layout_width="wrap_content"
    android:layout_height="250dp"
    android:layout_below="@+id/textView4"
    android:dividerHeight="20dp">

 </ListView>

<TextView
    android:id="@+id/textView5"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentTop="true"
    android:layout_marginRight="18dp"
    android:layout_toLeftOf="@+id/textView2"
    android:text="@string/viewname"
    android:textColor="@color/yellow"
    android:textSize="@dimen/sixtn" />

4

2 回答 2

0

我认为您的 JSON-String-handling 有一些问题，请尝试：

JSONObject object = new JSONObject(result);
JSONArray Jarray = object.getJSONArray("atendees");

for (int i = 0; i < Jarray.length(); i++) {
    JSONObject Jasonobject = Jarray.getJSONObject(i);
}

你还必须为其他 json 表处理这个问题！

于 2013-04-29T13:17:40.020 回答
0

你在哪里声明 s 和 r 变量？

您必须在 for 循环之前声明 ArrayList 变量

检查您的 xml 列表视图，您可以为此提供固定大小。更改为包裹或填充父项

于 2013-04-29T13:03:33.220 回答