file - Unix process file with latest timstamp

Question

I'm making a program that will load data into table. I've already created the procedure. But I'm having a problem with handling the file, since there are multiple files in the directory with different timestamps.

I would like to ask what is the code to detect the LATEST timestamp of the feed and choose that one.

For example, the name of the feed is PRODUCTS_I03_20130429.dat where "PRODUCTS_I03" is just the name of the feed.

I just want to detect the latest feed through its timestamp.

Thank You in Advance!

Answer 1

 ls *.dat | python -c "import sys,re; print sorted(sys.stdin, key = lambda x: re.search( r'(\d+)\.dat', x).group(1))[-1]"

Answer 2

如果您使用的是 shell 脚本或命令行，请尝试“ls -t”，或者如果您希望它们以相反的顺序使用，请使用“ls -tr”

Answer 3

你可以这样：

$ latest=$(echo -e "PRODUCTS_I03_20130429.dat\nPRODUCTS_I03_20130428.dat"|sort -r -t"_" -k3|head -1)
$ echo ${latest%_*}
PRODUCTS_I03

只有当文件名中有两个时它才会起作用_。echo只是为了测试。您应该将其替换为您要检查的模式，例如ls -1 PRODUCTS_*_*.dat.

如果时间戳与文件的日期相同，您可以使用以下内容：

$ latest=$(ls -1rt|head -1)
$ echo ${latest%_*}

或者您可以使用获取（最后修改）时间戳的实际日期state -c %y $latest。