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我想在登录 Gmail 或 Yahoo 后检查 JSON URL,但条件失败,我正在尝试以下代码。

如何声明javascript,我声明的方式正确吗?

我正在关注这个链接,请通过它http://www.stevesaxon.me/posts/2011/window-external-notify-in-ios-uiwebview/

- (BOOL)webView:(UIWebView *)webView
shouldStartLoadWithRequest:(NSURLRequest *)request
 navigationType:(UIWebViewNavigationType)navigationType

{   
    //_url = [[NSURL alloc] initWithString:websiteUrl];
    _url = [[NSURL alloc] initWithString:@"JSON URL"];
    if(_url)
    {

        if([_url isEqual:[request URL]])
        {
            return YES;
        }

        [_url release];
    }

    _url = [[request URL] retain];
    NSString* scheme = [_url scheme];

    //Condition fails here after logged in

    if([scheme isEqualToString:@"acs"])
    {
        // parse the JSON URL parameter into a dictionary
        NSDictionary* pairs = [self parsePairs:[_url absoluteString]];
        if(pairs)
        {
            WACloudAccessToken* accessToken;
            accessToken = [[WACloudAccessToken alloc] initWithDictionary:pairs];
            [WACloudAccessControlClient setToken:accessToken];

            [self dismissModalViewControllerAnimated:YES];
        }

        return NO;
    }

    [NSURLConnection connectionWithRequest:request delegate:self];

    return NO;

}



- (void)connectionDidFinishLoading:(NSURLConnection *)connection

{
    if(_data)
    {
        NSString* content = [[NSString alloc] initWithData:_data
                                                  encoding:NSUTF8StringEncoding];

        [_data release];
        _data = nil;

        NSString *jsString = @"window.external =\
        {\
        'Notify': function(s) { document.location = 'acs://settoken?token=' + s; },\
        'notify': function(s) { document.location = 'acs://settoken?token=' + s; }\
        }";

        content = [jsString stringByAppendingString:content];

        //NSURL *url = [[NSURL alloc] initWithString:websiteUrl];
        NSURL *url = [[NSURL alloc] initWithString:@"JSON URL"];
        [webView loadHTMLString:content baseURL:url];
    }

}
4

1 回答 1

1
        NSString *jsString = @"window.external =\
        {\
        'Notify': function(s) { document.location = 'acs://settoken?token=' + s; },\
        'notify': function(s) { document.location = 'acs://settoken?token=' + s; }\
        }";

应该:

        NSString *jsString = @"<script type='text/javascript'>\
        window.external =\
        {\
        'Notify': function(s) { document.location = 'acs://settoken?token=' + s; },\
        'notify': function(s) { document.location = 'acs://settoken?token=' + s; }\
        }\
        </script>";

顺便说一句,粗略的一瞥表明您的内存管理存在一些问题(_url正在泄漏,content正在泄漏)。如果您不确定如何处理手动内存管理,我强烈建议您打开 ARC(自动引用计数)。

于 2013-04-29T17:09:27.673 回答