4

在 SQL Server 2008 中,我得到以下结果:

 contact  phone       address    email
 Name1    435551123     
 Name1                street 1  
 Name1                           name1@domain.com
 Name2    654987624
 Name2                street2   
 Name2                           name2@domanin.com

我想像下面这样“压缩”它:

 contact  phone       address    email
 Name1    435551123   street 1   name1@domain.com       
 Name2    654987624   street2    name2@domanin.com
4

2 回答 2

8

Try the Query

select
contact,
max(phone),
max(address),
max(email)
from table_name
group by contact

SQL Fiddle

于 2013-04-29T08:27:56.283 回答
2

您可以使用 aCTE和一些OVER子句

WITH CTE AS (
  SELECT [contact], 
         [phone]=MAX(PHONE)OVER(PARTITION BY CONTACT), 
         [address]=MAX(address)OVER(PARTITION BY CONTACT),  
         [email]=MAX(email)OVER(PARTITION BY CONTACT),  
          RN = Row_number() 
                OVER( 
                partition BY [contact] 
                ORDER BY [contact])
  FROM dbo.Address) 
SELECT [contact], [phone], [address], [email] 
FROM CTE 
WHERE RN = 1

结果:

CONTACT PHONE       ADDRESS         EMAIL
Name1   435551123   street 1        name1@domain.com
Name2   654987624   street2         name2@domanin.com

演示

于 2013-04-29T08:34:37.040 回答