15

我需要做一些相当简单但没有哈希映射硬编码的事情。

我有一个 String s，它是西里尔文我需要一些关于如何使用自定义过滤器将其转换为拉丁字符的示例（如果 String s = sniff，请给出一个纯拉丁示例，以免混淆任何人；我希望它查找嗅探并将它们更改为其他内容（也可能有组合）。

我可以看到 ICU4j 可以做这种事情，但我不知道如何实现它，因为我找不到任何工作示例（或者我只是愚蠢）。

任何帮助表示赞赏。

谢谢

此致，

PS我需要批量翻译。我不关心样式或动态音译，只是关于 ICU4j 批量音译器的一些基本示例。

KI实际上得到了它。

import com.ibm.icu.text.Transliterator;


public class BulgarianToLatin {


    public static String BULGARIAN_TO_LATIN = "Bulgarian-Latin/BGN";

    public static void main(String[] args) {
        String bgString = "Джокович";

        Transliterator bulgarianToLatin = Transliterator.getInstance(BULGARIAN_TO_LATIN);
        String result1 = bulgarianToLatin.transliterate(bgString);
        System.out.println("Bulgarian to Latin:" + result1);

    }

}

也是基于规则的音译的最后一次编辑（如果您不想使用预先存在的一次或只是想要定制的东西）

import com.ibm.icu.text.Transliterator;

public class BulgarianToLatin {


    public static String BULGARIAN_TO_LATIN = "Bulgarian-Latin/BGN";

    public static void main(String[] args) {
        String bgString = "а б в г д е ж з и й к л м н о п р с т у ф х ц ч ш щ ю я  \n Юлиян Джокович";

        String rules="::[А-ЪЬЮ-ъьюяѢѣѪѫ];" +
        "Б > B;" +
        "б > b;" +
        "В > V;" +
        "ТС > TS;" +
        "Тс > Ts;" +
        "ч > ch;" +
        "ШТ > SHT;" +
        "Шт > Sht;" +
        "шт > sht;" +
        "{Ш}[[б-джзй-нп-тф-щь][аеиоуъюяѣѫ]] > Sh;" +
        "Я > YA;" +
        "я > ya;";
        Transliterator bulgarianToLatin = Transliterator.createFromRules("temp", rules, Transliterator.FORWARD);

        String result1 = bulgarianToLatin.transliterate(bgString);
        System.out.println("Bulgarian to Latin:" + result1);

    }

}
4

1 回答 1

23

我写了一种将西里尔字母音译为拉丁语的方法，也许这对 smb 有用。

public static String transliterate(String message){
    char[] abcCyr =   {' ','а','б','в','г','д','е','ё', 'ж','з','и','й','к','л','м','н','о','п','р','с','т','у','ф','х', 'ц','ч', 'ш','щ','ъ','ы','ь','э', 'ю','я','А','Б','В','Г','Д','Е','Ё', 'Ж','З','И','Й','К','Л','М','Н','О','П','Р','С','Т','У','Ф','Х', 'Ц', 'Ч','Ш', 'Щ','Ъ','Ы','Ь','Э','Ю','Я','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
    String[] abcLat = {" ","a","b","v","g","d","e","e","zh","z","i","y","k","l","m","n","o","p","r","s","t","u","f","h","ts","ch","sh","sch", "","i", "","e","ju","ja","A","B","V","G","D","E","E","Zh","Z","I","Y","K","L","M","N","O","P","R","S","T","U","F","H","Ts","Ch","Sh","Sch", "","I", "","E","Ju","Ja","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
    StringBuilder builder = new StringBuilder();
    for (int i = 0; i < message.length(); i++) {
        for (int x = 0; x < abcCyr.length; x++ ) {
            if (message.charAt(i) == abcCyr[x]) {
                builder.append(abcLat[x]);
            }
        }
    }
    return builder.toString();
}
于 2015-03-31T08:32:32.973 回答