0

简单的问题。我有以下自定义查询。如何让它通过“echo”生成数组的 html 列表？

$q_result = $wpdb->get_col("SELECT DISTINCT {$wpdb->terms}.name FROM {$wpdb->terms}
        INNER JOIN {$wpdb->term_taxonomy} ON {$wpdb->term_taxonomy}.term_id = {$wpdb->terms}.term_id
        INNER JOIN {$wpdb->term_relationships} ON {$wpdb->term_taxonomy}.term_taxonomy_id = {$wpdb->term_relationships}.term_taxonomy_id
        WHERE {$wpdb->term_taxonomy}.taxonomy = 'series' AND {$wpdb->term_relationships}.object_id IN (
        SELECT object_id FROM {$wpdb->term_relationships}
        INNER JOIN {$wpdb->term_taxonomy} ON {$wpdb->term_taxonomy}.term_taxonomy_id = {$wpdb->term_relationships}.term_taxonomy_id
        WHERE {$wpdb->term_taxonomy}.taxonomy = 'media_type' AND {$wpdb->term_taxonomy}.term_id = '16'
        ORDER BY {$wpdb->terms}.term_order DESC
        ) ORDER BY {$wpdb->terms}.term_order ASC");
4

1 回答 1

0

foreach您可以使用-遍历数组

foreach( $q_result as $result ){
   echo "<a href='/series/".$result."/>".$result."</a>";
}

如果还希望它显示 HTML，则必须回显正确的 HTML 标记。上述内容适用于该术语的链接 - 格式为 TAXONOMY/TERM_SLUG 但是您只返回名称，您需要获取名称和使用的 slugget_results()才能正确执行。

使用表别名重新格式化示例，返回术语和 slug：

$sql = <<<SQL
    SELECT DISTINCT t.name, t.slug 
    FROM {$wpdb->terms} t
    INNER JOIN {$wpdb->term_taxonomy} tt 
        ON tt.term_id = t.term_id and tt.taxonomy = 'series'
    INNER JOIN {$wpdb->term_relationships} tr 
        ON tt.term_taxonomy_id = tr.term_taxonomy_id
    WHERE tr.object_id IN (
        SELECT object_id 
        FROM {$wpdb->term_relationships} tr2
        INNER JOIN {$wpdb->term_taxonomy} tt2 
            ON tt2.term_taxonomy_id = tr2.term_taxonomy_id AND tt2.taxonomy = 'media_type' AND tt2.term_id = '16'
        ORDER BY {$wpdb->terms}.term_order DESC
    ) 
    ORDER BY {$wpdb->terms}.term_order ASC
SQL;

$terms = $wpdb->get_results( $sql );
for ( $terms as $term ){
    echo "<a href='/series/{$term->slug}/'>{$term->name}</a><br/>";
}
于 2013-04-29T05:15:13.680 回答