或许像这样:
with cte as (
select base = 1 + u + t*3 from (
select 0 as u union all select 1 union all select 2
) T1
cross join (
select 0 as t union all select 1 union all select 2
) T2
), data as (
select *
from (
values (1,1,2,3,3,5,7,4,2,1)
) data(x0,x1,x2,x3,x4,x5,x6,x7,x8,x9)
)
select cte.base
,case when x0>=base then 'X' else ' ' end as x0
,case when x1>=base then 'X' else ' ' end as x1
,case when x2>=base then 'X' else ' ' end as x2
,case when x3>=base then 'X' else ' ' end as x3
,case when x4>=base then 'X' else ' ' end as x4
,case when x5>=base then 'X' else ' ' end as x5
,case when x6>=base then 'X' else ' ' end as x6
,case when x7>=base then 'X' else ' ' end as x7
,case when x8>=base then 'X' else ' ' end as x8
,case when x9>=base then 'X' else ' ' end as x9
from cte
cross join data
order by base desc
;
这很好地产生了这个直方图:
base x0 x1 x2 x3 x4 x5 x6 x7 x8 x9
----------- ---- ---- ---- ---- ---- ---- ---- ---- ---- ----
9
8
7 X
6 X
5 X X
4 X X X
3 X X X X X
2 X X X X X X X
1 X X X X X X X X X X
请记住首先将您的数据转换为单行。
为了更紧凑的演示,将各种数据列连接成一个长字符串。