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我想实现一个处理屏幕开/关的服务。为此，我创建BootReceiver了在启动完成时调用并在我启动服务的过程中。但是，我ScreenBroadcastReceiver的从来没有被调用过，为什么？我是不是在错误的地方注册了它，我是在服务的创建上做的...请帮助我应该在哪里注册它？

因此，应用程序应该在后台运行（没有用户交互），它会记录屏幕的开启和关闭活动。我已经启动了这些代码，但似乎我需要注册我的 ScreenBroadcastReceiver 广播接收器。如果我这样做 onCreate 的服务。我应该改变它吗？我的最终目标是在后台运行这个应用程序，这样应用程序就可以在没有用户交互的情况下工作

这是一开始就调用的 BootReceiver： 

public class BootReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        Log.w("TAG", "BootReceiver");

        Intent service = new Intent(context, ScreenListenerService.class);
            context.startService(service);

    }

}

这是服务：

public class ScreenListenerService extends Service {


public void onCreate(){
    super.onCreate();
    Log.w("TAG", "ScreenListenerService---OnCreate ");

            IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
    filter.addAction(Intent.ACTION_SCREEN_OFF);
    BroadcastReceiver screenOnReceiver = new ScreenBroadcastReceiver();
    registerReceiver(screenOnReceiver, filter);
}


 @Override
 public int onStartCommand(Intent intent, int flags, int startId) {

        Log.w("TAG", "ScreenListenerService---onStart ");

         return START_STICKY;
    }

@Override
public IBinder onBind(Intent intent) {
    // TODO Auto-generated method stub
    return null;
}

}

这是 ScreenBroadcastReceiver：

public class ScreenBroadcastReceiver extends BroadcastReceiver {

   ///this part is never called, even if the screen is turned on/off.
    public static boolean screenOff;

    @Override
    public void onReceive(Context context, Intent intent) {

        if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {

            screenOff = true;
            System.out.println("SCREEN TURNED OFF on BroadcastReceiver");
        } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {

            screenOff = false;
            System.out.println("SCREEN TURNED ON on BroadcastReceiver");
        }
        Intent i = new Intent(context, ScreenListenerService.class);
        i.putExtra("screen_state", screenOff);
        context.startService(i);

    }

}

和清单：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.test"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk android:minSdkVersion="10" />
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED"/>
    <application
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name" >
        <activity
            android:name=".main"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>


         <service android:name=".ScreenListenerService"></service>

        <receiver android:name=".BootReceiver">
            <intent-filter>
                <action android:name="android.intent.action.BOOT_COMPLETED" />
                 <action android:name="android.intent.action.ACTION_EXTERNAL_APPLICATIONS_AVAILABLE" />
            </intent-filter>
        </receiver>

    </application>

</manifest>

更新： 可以在模拟器中测试这段代码并让我知道结果吗？

4

1 回答 1

6

BroadcastReceiver在onStart()方法中注册您的

@Override
public void onStart(Intent intent, int startId) {
    try {

        IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
        filter.addAction(Intent.ACTION_SCREEN_OFF);
        BroadcastReceiver mReceiver = new ScreenReceiver();
        registerReceiver(mReceiver, filter);

    } catch (Exception e) {
    }
}
于 2013-04-29T04:37:25.623 回答