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SELECT (res.phone_number_count + res.computer_count) AS user_count FROM (
    SELECT COUNT(DISTINCT phone_number_id) AS phone_number_count, COUNT(DISTINCT computer_id) AS computer_count
    FROM opinions
    WHERE case_id = 1
) AS res;

我正在尝试计算唯一的phone_number_ids 和computer_ids。

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1 回答 1

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怎么样:

SELECT COUNT(DISTINCT phone_number_id) + COUNT(DISTINCT computer_id) AS user_count
FROM opinions
WHERE case_id = 1
于 2013-04-27T17:12:10.880 回答