jquery - jQuery 1.9。[value!=""] 选择器

Question

如果至少有 2 个名称为选项 [] 的输入被填充，我需要 value is not empty 选择器来计数。我之前有 jquery 1.7.2 而不是 value!="" 选择器工作。

$('input[name="choices[]"][value!=""]').length

现在我升级了 jquery 1.9.1，这总是返回所有字段的数量，因为所有字段都被填充了，即使它们都没有被填充。有没有其他选择？

Answer 1

That's not working anymore because there's a difference between the current value of a field and the value attribute (which typically holds the original value as of when the HTML was parsed).

You'll probably have to throw a not in there:

$('input[name="choices[]"]').not(function() {
    return !!this.value;
}).length

...or filter:

$('input[name="choices[]"]').not(function() {
    return !this.value;
}).length

Answer 2

你可以简单地这样做：

$('input[name="choices[]"]').filter(function() {
     return $(this).val() != "";
}).length