7

我希望我只是在这里做一些愚蠢的事情......

我正在尝试为 a 设置 JPA 注释Map<String, Phone>并获取以下堆栈跟踪。

Exception [EclipseLink-6069] (Eclipse Persistence Services - 2.4.1.v20121003-ad44345): org.eclipse.persistence.exceptions.QueryException
Exception Description: The field [EMPLOYEE.PHONE_TYPE] in this expression has an invalid table in this context.
Query: ReadAllQuery(name="phones" referenceClass=Phone )
    at org.eclipse.persistence.exceptions.QueryException.invalidTableForFieldInExpression(QueryException.java:739)
    at org.eclipse.persistence.internal.expressions.FieldExpression.validateNode(FieldExpression.java:281)
    at org.eclipse.persistence.expressions.Expression.normalize(Expression.java:3259)
    at org.eclipse.persistence.internal.expressions.DataExpression.normalize(DataExpression.java:369)
    at org.eclipse.persistence.internal.expressions.FieldExpression.normalize(FieldExpression.java:208)
    at org.eclipse.persistence.internal.expressions.SQLSelectStatement.normalize(SQLSelectStatement.java:1377)
    at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.buildNormalSelectStatement(ExpressionQueryMechanism.java:546)
    at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.prepareSelectAllRows(ExpressionQueryMechanism.java:1700)
    at org.eclipse.persistence.queries.ReadAllQuery.prepareSelectAllRows(ReadAllQuery.java:721)
    at org.eclipse.persistence.queries.ReadAllQuery.prepare(ReadAllQuery.java:657)
    at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:614)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.checkPrepare(ObjectLevelReadQuery.java:883)
    at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:575)
    at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:820)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109)
    at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197)
    at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584)
    at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:112)
    at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:99)
    at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88)
    at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiateImpl(UnitOfWorkValueHolder.java:161)
    at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiate(UnitOfWorkValueHolder.java:222)
    at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88)
    at org.eclipse.persistence.indirection.IndirectMap.buildDelegate(IndirectMap.java:110)
    at org.eclipse.persistence.indirection.IndirectMap.getDelegate(IndirectMap.java:330)
    at org.eclipse.persistence.indirection.IndirectMap.size(IndirectMap.java:637)
    at org.eclipse.persistence.internal.queries.MapContainerPolicy.sizeFor(MapContainerPolicy.java:830)
    at org.eclipse.persistence.internal.indirection.TransparentIndirectionPolicy.instantiateObject(TransparentIndirectionPolicy.java:386)
    at org.eclipse.persistence.mappings.ForeignReferenceMapping.buildCloneFromRow(ForeignReferenceMapping.java:285)
    at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildAttributesIntoWorkingCopyClone(ObjectBuilder.java:1594)
    at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildWorkingCopyCloneFromRow(ObjectBuilder.java:1741)
    at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObjectInUnitOfWork(ObjectBuilder.java:668)
    at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:605)
    at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:564)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.buildObject(ObjectLevelReadQuery.java:777)
    at org.eclipse.persistence.queries.ReadAllQuery.registerResultInUnitOfWork(ReadAllQuery.java:783)
    at org.eclipse.persistence.queries.ReadAllQuery.executeObjectLevelReadQuery(ReadAllQuery.java:434)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeDatabaseQuery(ObjectLevelReadQuery.java:1150)
    at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:852)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109)
    at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393)
    at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197)
    at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584)
    at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1549)
    at org.eclipse.persistence.internal.jpa.QueryImpl.executeReadQuery(QueryImpl.java:231)
    at org.eclipse.persistence.internal.jpa.QueryImpl.getResultList(QueryImpl.java:411)
    at aaa.Test.main(Test.java:20)

创建的表如下所示:

EMP_PHONE
=================================
EMP_ID    PHONES_ID    PHONE_TYPE
------    ---------    ----------
42        1            NULL


EMPLOYEE
=================================
ID
--
42


PHONE
=================================
ID    NUM
--    --------
1     867-5309

似乎告诉我正在发生一些奇怪的NULL PHONE_TYPE事情,而 eclipselink 正在寻找的方式EMPLOYEE.PHONE_TYPE让我认为它正在考虑从PHONE->EMPLOYEE而不是相反的关系。

JPA 实体定义如下。电话地图是单向的,电话对象应该由多个员工共享(不是我的实际类型,但这个简化的示例演示了问题)

@Entity
public class Employee {
    @Id private long id;

    @OneToMany(cascade=CascadeType.ALL)
    @JoinTable(name="EMP_PHONE", joinColumns=@JoinColumn(name="EMP_ID"))
    @MapKeyColumn(name="PHONE_TYPE")
    private Map<String, Phone> phones = new HashMap<String, Phone>();

    public Employee() {}
    public Employee(long id) {
        this.id = id;
    }
    public long getId() {
        return id;
    }
    public Map<String, Phone> getPhones() {
        return phones;
    }
}

@Entity
public class Phone {
    @Id
    private long id;
    private String num;

    public String getNum() {
        return num;
    }
    public Phone() {}
    public Phone(String num) {
        this.num = num;
    }
    public Phone(long id, String num) {
        this.id = id;
        this.num = num;
    }
    public long getId() {
        return id;
    }
}

使用以下测试代码

EntityManagerFactory factory = Persistence.createEntityManagerFactory("test");
EntityManager em = factory.createEntityManager();
Employee employee = new Employee(42);
// exception will occur with or without phones added to the map
employee.getPhones().put("home", new Phone(1, "867-5309"));
em.getTransaction().begin();
em.persist(employee);
em.getTransaction().commit();

Query q = em.createQuery("select o from Employee o");
q.setHint("javax.persistence.cache.storeMode", "REFRESH");
q.getResultList();  // EXCEPTION THROWN HERE

和persistence.xml:

<?xml version='1.0' encoding='UTF-8' ?>
<persistence xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'
    xsi:schemaLocation='http://java.sun.com/xml/ns/persistence
           http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd'
    version='2.0' xmlns='http://java.sun.com/xml/ns/persistence'>
    <persistence-unit name='test' transaction-type='RESOURCE_LOCAL'>
        <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
        <class>aaa.Phone</class>
        <class>aaa.Employee</class>
        <shared-cache-mode>NONE</shared-cache-mode>
        <properties>
            <property name='javax.persistence.jdbc.user' value='uuuuuuuu' />
            <property name='javax.persistence.jdbc.password' value='pppppppp' />
            <property name='javax.persistence.jdbc.driver'
                      value='oracle.jdbc.driver.OracleDriver' />
            <property name='javax.persistence.jdbc.url' 
                      value='jdbc:oracle:thin:@localhost:1521:xe' />
            <property name='eclipselink.ddl-generation' 
                      value='drop-and-create-tables' />
            <property name='eclipselink.ddl-generation.output-mode' value='database' />
        </properties>
    </persistence-unit>
</persistence>

我在 Windows 7 上运行,使用 Oracle XE 11g 作为数据库。提前感谢您的任何见解!

4

1 回答 1

12

这看起来像 EclipseLink 错误364922

具有单向 OneToMany 属性和 @MapKeyColumn 注释的实体创建了正确的数据库表,映射表包含“键列,但持久化实体仅填充 id 列而不填充键列。持久操作不会抛出一个错误,但随后的查询很快就会失败并出现以下错误: 异常描述:此表达式中的字段 [ORGANIZATION.MAILINGADDRESSES_KEY] 在此上下文中具有无效的表。

对于它的价值,我使用 Hibernate/H2 测试了您的代码,它工作正常。

更新

我刚刚用 EclipseLink 测试了这个。如果您为 显式设置表,MapKeyColumn则正确填充该键。IE:

@MapKeyColumn(name="PHONE_TYPE", table="EMP_PHONE")

于 2013-04-30T16:32:16.893 回答