macos - 将字符串读入变量，直到 BASH 中的某个单词

Question

我有一个输出如下内容的程序：

stuff=Some text with spaces and other $pecial characters stuff2=1 stuff3=0

我试图在变量中获取所有字符串，直到 stuff2=1，所以变量将是：

stuff=Some text with spaces and other $special characters

我试过这个：

for word in $output
while [ $word != "stuff2=1" ]
do
   var+=" "$word
done
done

但我得到的只是一遍又一遍的“stuff=Some”。

Answer 1

可以在 bash 本身中完成

stuff=${stuff/stuff2=1*/}

Answer 2

这个怎么样？

stuff='Some text with spaces and other $pecial characters stuff2=1 stuff3=0'

var=""
for word in $stuff
do
  if [ "$word" == "stuff2=1" ]
     then
    break
  fi
  if [ "$var" != "" ]
  then
    var="${var} "
  fi
  var="${var}${word}"
done
echo "$var"

Answer 3

您可以通过简单的 bash 参数扩展来实现这一点：

line='stuff=Some text with spaces and other $pecial characters stuff2=1 stuff3=0'
truncated=${line% stuff2=1*}
echo "$truncated"

stuff=Some text with spaces and other $pecial characters

当您需要“取消引用”它时，引用变量至关重要。

Answer 4

$ eval $(sed "s/=/='/;s/ [^ ]*=.*/'/")

$ echo $stuff
Some text with spaces and other $pecial characters