我正在尝试从头开始创建一个查找方法，以查看两个对象是否相等，因为某些成员是相等的，使用 Equals 方法来做到这一点。我知道使用 Find/Contains 方法会更快，但我不能使用它们。该方法的签名是“static int Find(List c, Coffee x)” Find 在 c 中寻找 x，如果 x 存在于 c 中，则返回有效索引（例如，0, 1），否则返回 -1。必须使用 equals 方法来确定等价性。如果传递的对象不等于列表中的当前对象，则将其添加到列表中（列表包含从基类派生的两种类型的对象，因此列表可以存储这两种类型）。等价性由名称、成本、需求、保存成本和烘焙类型定义（常规）和无咖啡因的名称、成本、需求、保存成本和最小数量。这是我到目前为止所拥有的：
static void Main(string[] args)
{
// Create objects and references
Coffee obv = new Coffee();
Decaf decafCoffee = null;
Regular regularCoffee = null;
List<Coffee> inventory = new List<Coffee>();
// Prompt user for input and store it as a string
Console.Write("Enter q to quit or the whole data as a comma delimited string using the following format Name,D,C,D:minQ or R:roast ");
string s = Console.ReadLine();
// Loop
while (!s.ToLower().Equals("q"))
{
// Split string up and assign componets to variables
string[] values = s.Split(",".ToCharArray(), StringSplitOptions.RemoveEmptyEntries);
string name = values[0];
string demand = (values[1]);
string cost = (values[2]);
string type = values[3];
// Check for > 0 and convert to numbers
float D = CheckDemand(demand);
float C = CheckCost(cost);
float M = 0;
if (type.StartsWith("D:"))
{
type = Regex.Match(type, @"\d+").Value;
M = CheckMin(type);
decafCoffee = new Decaf(name, D, C, M);
inventory.Add(decafCoffee);
}
else if (type.StartsWith("R:"))
{
if (type.Contains("light"))
{
M = 1;
regularCoffee = new Regular(name, D, C, M);
inventory.Add(regularCoffee);
}
else if (type.Contains("medium"))
{
M = 2;
regularCoffee = new Regular(name, D, C, M);
inventory.Add(regularCoffee);
}
else if (type.Contains("dark"))
{
M = 3;
regularCoffee = new Regular(name, D, C, M);
inventory.Add(regularCoffee);
}
else Console.WriteLine("\nError, please enter all lower case \"dark\", \"medium\", or \"light\" next time.");
}
else Console.WriteLine("\nError, please enter either \"D:\" followed by a number or \"R:\" followed by roast type next time.");
Console.Write("\nEnter q to quit or the whole data as a comma delimited string using the following format Name,D,C,D:minQ or R:roast: ");
s = Console.ReadLine();
} // End loop
// Sort and display values
var sortedList = inventory.OrderBy(i => i.Q()).ToList();
Console.WriteLine("\nName \t C ($) Demand \t Detail Q(lbs.) TAC
for (int j = 0; j < inventory.Count; j++)
{
Console.WriteLine("{0}", sortedList[j].toString());
}
Console.WriteLine(obv.toStringQ());
这就是我所拥有的 equals 方法：
public override bool Equals(object obj)
{
if (obj is Coffee)
{
bool isNameEqual = Name.Equals(this.Name);
bool isuCostEqual = Cost.Equals(this.Cost);
bool isDemandEqual = Demand.Equals(this.Demand);
bool ishCostEqual = h.Equals(this.h);
bool isMinEqual = getQ.Equals(this.getQ);
return (isNameEqual && isuCostEqual && isDemandEqual && ishCostEqual && isMinEqual);
}
return false;
}
如何使用 find 方法？