34

我正在尝试导入 CSV 文件，使用表单从客户端系统上传文件。获得文件后，我将提取其中的一部分并在我的应用程序中填充模型。但是，当我遍历上传文件中的行时，出现“迭代器应该返回字符串，而不是字节”错误。我花了几个小时尝试不同的东西并阅读我能找到的所有内容，但似乎无法解决它（注意，我对 Django 相对较新 - 运行 1.5 - 和 python - 运行 3.3）。我删除了一些东西以解决错误并像这样运行它以确保它仍然存在。在 tools_clubs_import() 中执行“for clubs in club_list”行时显示错误：

根据下面标记的答案，以下是正确的 views.py 有效：

import csv
from io import TextIOWrapper
from django.shortcuts import render
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse
from rank.forms import ClubImportForm

def tools_clubs_import(request):
    if request.method == 'POST':
        form = ClubImportForm(request.POST, request.FILES)
        if form.is_valid():
            # the following 4 lines dumps request.META to a local file
            # I saw a lot of questions about this so thought I'd post it too
            log = open("/home/joel/meta.txt", "w")
            for k, v in request.META.items():
                print ("%s: %s\n" % (k, request.META[k]), file=log)
            log.close()
            # I found I didn't need errors='replace', your mileage may vary
            f = TextIOWrapper(request.FILES['filename'].file,
                    encoding='ASCII')
            club_list = csv.DictReader(f)
            for club in club_list:
                # do something with each club dictionary entry
                pass
            return HttpResponseRedirect(reverse('rank.views.tools_clubs_import_show'))
    else:
        form = ClubImportForm()

    context = {'form': form, 'active_menu_item': 4,}
    return render(request, 'rank/tools_clubs_import.html', context)

def tools_clubs_import_show(request):
    return render(request, 'rank/tools_clubs_import_show.html')

以下是我提交的原始版本（生成表单的 html 包含在此代码列表的底部：

views.py
--------
import csv
from django.shortcuts import render
from django.http import HttpResponseRedirect
from rank.forms import ClubImportForm

def tools(request):
    context = {'active_menu_item': 4,}
    return render(request, 'rank/tools.html', context)

def tools_clubs(request):
    context = {'active_menu_item': 4,}
    return render(request, 'rank/tools_clubs.html', context)

def tools_clubs_import(request):
    if request.method == 'POST':
        form = ClubImportForm(request.POST, request.FILES)
        if form.is_valid():
            f = request.FILES['filename']
            club_list = csv.DictReader(f)
            for club in club_list:
                # error occurs before anything here is executed
                # process here... not included for brevity
            return HttpResponseRedirect(reverse('rank.views.tools_clubs_import_show'))
    else:
        form = ClubImportForm()

    context = {'form': form, 'active_menu_item': 4,}
    return render(request, 'rank/tools_clubs_import.html', context)

def tools_clubs_import_show(request):
    return render(request, 'rank/tools_clubs_import_show.html')

forms.py
--------
from django import forms


class ClubImportForm(forms.Form):
    filename = forms.FileField(label='Select a CSV to import:',)


urls.py
-------
from django.conf.urls import patterns, url
from rank import views

urlpatterns = patterns('',
    url(r'^tools/$', views.tools, name='rank-tools'),
    url(r'^tools/clubs/$', views.tools_clubs, name='rank-tools_clubs'),
    url(r'^tools/clubs/import$',
        views.tools_clubs_import,
        name='rank-tools_clubs_import'),
    url(r'^tools/clubs/import/show$',
        views.tools_clubs_import_show,
        name='rank-tools_clubs_import_show'),
)


tools_clubs_import.html
-----------------------
{% extends "rank/base.html" %}
{% block title %}Tools/Club/Import{% endblock %}
{% block center_col %}

    <form enctype="multipart/form-data" method="post" action="{% url 'rank-tools_clubs_import' %}">{% csrf_token %}
        {{ form.as_p }}
        <input type="submit" value="Submit" />
    </form>

{% endblock %}

异常值：

迭代器应该返回字符串，而不是字节（您是否以文本模式打开文件？）

异常位置：/usr/lib/python3.3/csv.py 在字段名中，第 96 行

4

3 回答 3

61

request.FILES为您提供二进制文件，但该csv模块希望使用文本模式文件。

您需要将文件包装在一个io.TextIOWrapper()实例中，并且您需要弄清楚编码：

from io import TextIOWrapper

f = TextIOWrapper(request.FILES['filename'].file, encoding=request.encoding)

如果您charset从标头中获取参数（Content-Type如果提供）可能会更好；这就是客户告诉你的字符集。

您无法解决需要知道文件数据的正确编码的问题；您可以强制解释为 ASCII，例如，通过提供errors关键字（将其设置为“替换”或“忽略”），但这确实会导致数据丢失：

f = TextIOWrapper(request.FILES['filename'].file, encoding='ascii', errors='replace')

使用 TextIOWrapper 仅在使用 Django 1.11 及更高版本时才有效（因为此变更集添加了所需的支持）。在早期版本中，您可以在事后对支持进行猴子补丁：

from django.core.files.utils import FileProxyMixin

if not hasattr(FileProxyMixin, 'readable'):
    # Pre-Django 1.11, add io.IOBase support, see
    # https://github.com/django/django/commit/4f474607de9b470f977a734bdd47590ab202e778        
    def readable(self):
        if self.closed:
            return False
        if hasattr(self.file, 'readable'):
            return self.file.readable()
        return True

    def writable(self):
        if self.closed:
            return False
        if hasattr(self.file, 'writable'):
            return self.file.writable()
        return 'w' in getattr(self.file, 'mode', '')

    def seekable(self):
        if self.closed:
            return False
        if hasattr(self.file, 'seekable'):
            return self.file.seekable()
        return True

    FileProxyMixin.closed = property(
        lambda self: not self.file or self.file.closed)
    FileProxyMixin.readable = readable
    FileProxyMixin.writable = writable
    FileProxyMixin.seekable = seekable
于 2013-04-26T18:42:41.787 回答
29

在 python 3 中，我使用了：

import csv
from io import StringIO
csvf = StringIO(xls_file.read().decode())
reader = csv.reader(csvf, delimiter=',')

xls_file 是从 POST 表单获取的文件。我希望它有所帮助。

于 2015-03-27T19:53:01.900 回答
0

融合你的两种方法，这在 Python 3.5.2 和 Django 1.9 中永远不会失败

delimitador = list_delimitadores[int(request.POST['delimitador'])][1]
try:
    text = TextIOWrapper(request.FILES['csv_x'].file, encoding='utf-8 ', errors='replace')
    reader = csv.reader(text, delimiter=delimitador)
except:
    text = StringIO(request.FILES['csv_x'].file.read().decode())
    reader = csv.reader(text, delimiter=delimitador)
于 2017-02-25T16:17:42.170 回答