linux - Extract string from output command

Question

My program output is as the following:

# myprogram list
val
val.dev
val.int
val.int.p1
val.int.p2
val.int.p3
val.int.p4
val.int.p5
val.dev.p6

I want to extract from the above output only strings under val.int. so I want to add something to the command in order to get the following output:

# myprogram list|<something options>
p1
p2
p3
p4
p5

Is it possible to do it with awk (or someting similar like sed) in only one call of awk?

Answer 1

awk 'NF>2 {print $3}' FS=.

• 将字段分隔符更改为.
• 打印字段 3

Answer 2

myCommand | sed -n 's/val\.int\.//p'

Answer 3

还有另一种解决方案，这个涉及grepPerl 正则表达式：

$ myprogram list | grep -Po "(?<=val\.int\.).*"

Answer 4

尝试这个：

awk -F'val.int.' '$0=$2' file

文件包含您的数据：

kent$ awk -F'val.int.' '$0=$2' file
p1
p2
p3
p4
p5