ios6 - 使用 SQLite3 从数据库中删除联系人。删除方法正在跳过 if 语句并显示 else

Question

我无法删除记录。代码看起来不错，我在 Xcode 端没有收到任何错误，但是当我运行应用程序并尝试删除记录时，它会跳过if并直接else显示我的错误代码：

Error: Failed to delete contact. 

我已遵循所有说明，所有其他功能都运行良好。我必须使用 SQLite3 进行删除。代码有什么问题？

- (IBAction)deleteData:(id)sender {
    sqlite3_stmt *statement;
    const char *dbpath = [_databasePath UTF8String];

    if (sqlite3_open(dbpath, &_contactDB) == SQLITE_OK)
    {
        NSString *deleteSQL = [NSString stringWithFormat:@"DELETE FROM CONTACTS (name, address, phone)VALUES (\"%@\", \"%@\", \"%@\")",
                               self.name.text, self.address.text, self.phone.text];

        const char *delete_stmt = [deleteSQL UTF8String];
        sqlite3_prepare_v2(_contactDB, delete_stmt, -1, &statement, NULL);
        if (sqlite3_step(statement) == SQLITE_DONE)
        {
            self.status.text = @"Contact Deleted";
            self.name.text = @"";
            self.address.text = @"";
            self.phone.text = @"";
        } else {
            self.status.text = @"Error! Failed to delete contact";
        }
        sqlite3_finalize(statement);
        sqlite3_close(_contactDB);
    }
}

Answer 1

你的DELETE语法是错误的。请阅读文档。

您可能想要删除由其 ID 值标识的记录：

DELETE FROM Contacts WHERE id = ?