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我绝对是一个 SQL 新手,所以也许你们可以帮助我理解一些东西,并可能帮助我解决我认为必须是一个简单问题的解决方案。

我运行这个查询,它返回我想要并且感觉正确的结果。

SELECT distinct 
   isnull(T3.[name],'') [Vendor Name]
  ,T1.[active] [Active]
  ,T1.[number] [Vendor Number]
  ,T1.[mnemonic] [Mnemonic]
  ,T1.[bank_acc] [Bank Account]
  ,isnull(T1.[our_acct_number],'') [Our Account Number]
  ,isnull(T1.[fed_id_num],'') [Fed ID]
  ,isnull((select  T2.[ap_contact_name] [AP Contact] from TABLE2 T2 
  where [ap_contact] = '1' and T2.[number] = T1.[number]),'') [AP Contact]
  ,isnull(T2.[ap_contact_phone],'') [Contact Phone Number]
  ,isnull(T1.[print_1099],'') [Print 1099?]
  ,isnull(T1.[expense_type],'') [Expense Type]
  ,isnull(T4.[remit_addr_1],'') [Remit Street Address]
  ,isnull(T4.[remit_addr_2],'') [Other Adress Info]
  ,isnull(T4.[remit_addr_3],'') [Remit City, State, Zip]
  ,isnull(T4.[remit_1099], '') [Remit 1099?] 


FROM 
TABLE1 T1
LEFT outer JOIN
TABLE2 T2
ON T1.[number] = T2.[number]
left outer join
TABLE3 T3
ON T1.[number] = T3.[number]
left outer join
TABLE4 T4
on T1.[number] = T4.[number]
left join
TABLE5 T5
ON T1.[number] = T5.[txn_vendor]
LEFT join
TABLE6 T6
ON T5.[txn_inv_num] = T6.[inv_num]


 WHERE
 T1.[active] ='Y'

 order by 
[Vendor Name]

但是,当我将此子查询添加到选择语句以返回每个供应商的最后付款日期时

 ,(SELECT
                 MAX(T6.[inv_date])
                 FROM
                Table6 T6
                WHERE

               T5.[txn_inv_num] = T6.[inv_num]
               group by T5.[txn_vendor],T5.[txn_inv_num]
                 )
                 [Last Pymt Date]

我得到了大约 20 行重复供应商和不同日期的结果。我正在尝试将每个供应商的最后付款日期添加到结果集中。

我也尝试过以其他方式使用虚拟表,但我没有运气。任何输入表示赞赏。

使用 SQL 服务器 2008。

4

1 回答 1

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而不是使用distinctuse group by。这是您的查询的一个版本,只需将 a 更改distinct为 agroup by并添加max()日期:

SELECT distinct 
   isnull(T3.[name],'') [Vendor Name]
  ,T1.[active] [Active]
  ,T1.[number] [Vendor Number]
  ,T1.[mnemonic] [Mnemonic]
  ,T1.[bank_acc] [Bank Account]
  ,isnull(T1.[our_acct_number],'') [Our Account Number]
  ,isnull(T1.[fed_id_num],'') [Fed ID]
  ,isnull((select  T2.[ap_contact_name] [AP Contact] from TABLE2 T2 
  where [ap_contact] = '1' and T2.[number] = T1.[number]),'') [AP Contact]
  ,isnull(T2.[ap_contact_phone],'') [Contact Phone Number]
  ,isnull(T1.[print_1099],'') [Print 1099?]
  ,isnull(T1.[expense_type],'') [Expense Type]
  ,isnull(T4.[remit_addr_1],'') [Remit Street Address]
  ,isnull(T4.[remit_addr_2],'') [Other Adress Info]
  ,isnull(T4.[remit_addr_3],'') [Remit City, State, Zip]
  ,isnull(T4.[remit_1099], '') [Remit 1099?],
  max(t6.inv_date) as [Last Pymt Date]


FROM 
TABLE1 T1
LEFT outer JOIN
TABLE2 T2
ON T1.[number] = T2.[number]
left outer join
TABLE3 T3
ON T1.[number] = T3.[number]
left outer join
TABLE4 T4
on T1.[number] = T4.[number]
left join
TABLE5 T5
ON T1.[number] = T5.[txn_vendor]
LEFT join
TABLE6 T6
ON T5.[txn_inv_num] = T6.[inv_num]


 WHERE
 T1.[active] ='Y'

group by
   isnull(T3.[name],'') [Vendor Name]
  ,T1.[active] [Active]
  ,T1.[number] [Vendor Number]
  ,T1.[mnemonic] [Mnemonic]
  ,T1.[bank_acc] [Bank Account]
  ,isnull(T1.[our_acct_number],'') [Our Account Number]
  ,isnull(T1.[fed_id_num],'') [Fed ID]
  ,isnull((select  T2.[ap_contact_name] [AP Contact] from TABLE2 T2 
  where [ap_contact] = '1' and T2.[number] = T1.[number]),'') [AP Contact]
  ,isnull(T2.[ap_contact_phone],'') [Contact Phone Number]
  ,isnull(T1.[print_1099],'') [Print 1099?]
  ,isnull(T1.[expense_type],'') [Expense Type]
  ,isnull(T4.[remit_addr_1],'') [Remit Street Address]
  ,isnull(T4.[remit_addr_2],'') [Other Adress Info]
  ,isnull(T4.[remit_addr_3],'') [Remit City, State, Zip]
  ,isnull(T4.[remit_1099], '') [Remit 1099?] 


 order by 
[Vendor Name]
于 2013-04-26T15:15:49.497 回答