3

我的 Listview 将项目数据模板化为标签。我正在为该标签设计一种样式,但我不知道如何访问父级的 (ListViewItem) IsSelected 属性。

编辑 - 尝试了以下建议,但仍然出现异常,这是我的完整代码:

 <Style x:Key="ListViewItemStyle" TargetType="ListViewItem">
                <Setter Property="SnapsToDevicePixels" Value="true"/>
                <Setter Property="OverridesDefaultStyle" Value="true"/>
                <Setter Property="Template">
                    <Setter.Value>
                        <ControlTemplate TargetType="ListViewItem">
                            <Border BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" Background="{TemplateBinding Background}" Padding="{TemplateBinding Padding}" SnapsToDevicePixels="true">
                                <GridViewRowPresenter HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"/>
                            </Border>
                        </ControlTemplate>
                    </Setter.Value>
                </Setter>
                <Style.Triggers>
                    <Trigger Property="IsSelected" Value="True">
                        <Setter Property="Background" Value="{StaticResource WindowBorderBrush}"/>
                        <Setter Property="Foreground" Value="White"/>
                    </Trigger>
                </Style.Triggers>
            </Style>
            <Style x:Key="GVLabelStyle"
                   BasedOn="{StaticResource LabelStyle}"
                   TargetType="Label">
                <Style.Triggers>
                    <MultiDataTrigger>
                        <MultiDataTrigger.Conditions>
                            <Condition  Property="{Binding Path=IsSelected, RelativeSource={RelativeSource FindAncestor}}" Value="True"/>
                        </MultiDataTrigger.Conditions>            
                        <Setter Property="Foreground" Value="White"/>
                    </MultiDataTrigger>
                </Style.Triggers>
            </Style>

            <DataTemplate x:Key="appTemplate">
                <Label Style="{StaticResource GVLabelStyle}"
                       Content="{Binding ProcessInfo.ProcessName}">
                               </Label>
            </DataTemplate>  

 <ListView Background="Transparent"
                  Name="mainContentHolder"
                  ItemsSource="{Binding}"
                  BorderBrush="Transparent"
                  ItemContainerStyle="{StaticResource ListViewItemStyle}">
                <ListView.View>
                <GridView ColumnHeaderContainerStyle="{StaticResource HeaderStyle}">
                    <GridViewColumn Header="Application" 
                                    CellTemplate="{StaticResource appTemplate}"/>
                    <GridViewColumn Header="Window Title"
                                    CellTemplate="{StaticResource wndTemplate}"
                                    Width="300"/>
                    <GridViewColumn Header="Date"
                                    CellTemplate="{StaticResource dateTemplate}"/>

                </GridView>
            </ListView.View>

        </ListView>
4

3 回答 3

4

您应该能够使用RelativeSource

<Condition Property="{Binding Path=IsSelected, RelativeSource={RelativeSource TemplatedParent}}" Value="True" />

编辑:尝试使用 aMultiDataTrigger而不是 a MultiTrigger。检查这个

于 2013-04-26T07:16:01.477 回答
0

ListView有分开SelectedItemTemplate的。所以你可以使用它。

于 2013-04-26T07:13:50.113 回答
0

为了节省您的时间,发布对我和 OP 都有效的语法:{Binding RelativeSource={RelativeSource AncestorType={x:Type ParentType}}, Path=ParentProperty}

于 2015-07-21T13:41:51.417 回答