我正在尝试测试 JMS 应用程序,消费者没有问题,但是当我尝试运行具有以下代码的生产者时
public class QueueProducer {
/**
* @param args
* @throws NamingException
* @throws JMSException
*/
public static void main(String[] args) throws JMSException, NamingException {
System.out
.println("--------Entering JMS Example QueueProducer--------");
Context context = QueueConsumer.getInitialContext();
QueueConnectionFactory queueConnectionFactory = (QueueConnectionFactory) context
.lookup("ConnectionFactory");
Queue queue = (Queue) context
.lookup("queue/zaneacademy_jms_tutorial_02");
QueueConnection queueConnection = queueConnectionFactory
.createQueueConnection();
QueueSession queueSession = queueConnection.createQueueSession(false,
QueueSession.AUTO_ACKNOWLEDGE);
queueConnection.start();
QueueProducer queueProducer = new QueueProducer();
queueProducer.sendMessage("Message 1 From QueueProducer...",
queueSession, queue);
System.out.println("--------Exiting JMS Example QueueProducer--------");
}
public void sendMessage(String text, QueueSession queueSession, Queue queue)
throws JMSException {
QueueSender queueSender = queueSession.createSender(queue);
TextMessage textMessage = queueSession.createTextMessage(text);
queueSender.send(textMessage);
System.out.println("Message Sent : "+textMessage.getText());
queueSender.close();
}
}
它只在生产者中显示消息,几秒钟后它显示此警告
WARN [SimpleConnectionManager] A problem has been detected with the connection to remote client 5c4o12- tsh1gl-hfybsrs4-1-hfybss2a-4, jmsClientID=b-l5ssbyfh-1-4srsbyfh-lg1hst-21o4c5. It is possible the client has exited without closing its connection(s) or the network has failed. All associated connection resources will be cleaned up.