regex - 如何在 Vim 中删除与模式匹配的所有行和后面的行？

Question

有一段文字

Title of the text

This line contains a word that is matched by the pattern and it should be deleted.
Next line is supposed to be deleted as well.

Loren ipsum dolorem...

This line contains a word that is matched by the pattern and it should be deleted.
And this one should be deleted

The end of the article

如何删除与第一行匹配的每一对行，例如“此行包含一个单词...”以及该行之后的行。结果将是：

Title of the text

Loren ipsum dolorem...

The end of the article

score 60 · Accepted Answer

您可以使用

:g/word/normal 2dd

这会找到 word 的所有实例，然后执行它之后的命令。在这种情况下，它2dd以正常模式执行

score 29 · Accepted Answer

:g[lobal]与具有范围的d[elete]命令一起使用以,+1删除匹配的行和下一行：

:g/word/,+1d

score 6 · Accepted Answer

6

您可以使用以下:g[lobal]命令：

:g/This line/norm 3dd

于 2013-04-25T19:27:58.280 回答

score 3 · Accepted Answer

3

另一种方式：g

:g/word/norm dj

于 2013-04-25T20:48:00.873 回答

score 2 · Accepted Answer

2

你可能想试试这个：

:g/your pattern go here/d

于 2015-03-20T04:44:44.463 回答

regex - 如何在 Vim 中删除与模式匹配的所有行和后面的行？

5 回答 5

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