4

我有一个 div 应用了以下渐变：

/* Mozilla Firefox */ 
background-image: -moz-linear-gradient(top, #2E2E28 0%, #4D4C48 100%);
/* Opera */ 
background-image: -o-linear-gradient(top, #2E2E28 0%, #4D4C48 100%);
/* Webkit (Safari/Chrome 10) */ 
background-image: -webkit-gradient(linear, left top, left bottom, color-stop(0, #2E2E28), color-stop(1, #4D4C48));
/* Webkit (Chrome 11+) */ 
background-image: -webkit-linear-gradient(top, #2E2E28 0%, #4D4C48 100%);
/* IE10+ */
background: -ms-linear-gradient(top,  #2E2E28 0%,#4D4C48 100%);
/* W3C */
background: linear-gradient(top,  #2E2E28 0%,#4D4C48 100%);

我怎样才能将“#2E2E28”更改为另一个数字，但仍然避免跨浏览器的噩梦？

4

3 回答 3

6

以下函数将采用两种颜色作为参数并返回您指定的样式字符串，并将适当的子字符串替换为给定的颜色。

您可以在这里看到这一点。

var makeGradientStyle = function(){
    var gradientString = '\
        /* Mozilla Firefox */ \
background-image: -moz-linear-gradient(top, {colour1} 0%, {colour2} 100%);\
        /* Opera */ \
        background-image: -o-linear-gradient(top, {colour1} 0%, {colour2} 100%);\
        /* Webkit (Safari/Chrome 10) */ \
        background-image: -webkit-gradient(linear, left top, left bottom, color-stop(0, {colour1}), color-stop(1, {colour2}));\
        /* Webkit (Chrome 11+) */ \
        background-image: -webkit-linear-gradient(top, {colour1} 0%, {colour2} 100%);\
        /* IE10+ */\
        background: -ms-linear-gradient(top,  {colour1} 0%,{colour2} 100%);\
        /* W3C */\
        background: linear-gradient(top,  {colour1} 0%,{colour2} 100%);\
    ';

    return function(colour1, colour2){
        return gradientString.replace(/\{colour1\}/g, colour1).replace(/\{colour2\}/g, colour2)
    }
}();

然后，您可以按以下方式申请。缺点在于您要替换整个样式字符串，但是您可以使用

var p = document.getElementById('p');

p.setAttribute('style', p.getAttribute('style') + '; ' + makeGradientStyle('#ff0000', '#0000ff'));
于 2013-04-25T16:03:55.857 回答
5

使用 jQuery，它将是：

$('.gradient').css({'background-image': 'linear-gradient(to top,  #2E2E28 0%, #4D4C48 100%)'});

对于野生动物园：

$('.gradient').css({'background-image': '-webkit-linear-gradient(top,  #2E2E28 0%, #4D4C48 100%)'});

请参阅此处以获取实时示例。

似乎可以跨浏览器工作。

编辑：

我做了一个小插件，可以帮助你使用不同的颜色：

;(function($) {
    var isSafari = /Safari/.test(navigator.userAgent) && /Apple Computer/.test(navigator.vendor);

    var methods = {
        init: function (settings) {

            settings = $.extend( {
              'colors'         : ['red', 'blue'],
              'direction'      : 'top'
            }, settings);

            return this.each(function(){
                if($.isArray(settings.colors) && settings.colors.length >= 2) {
                    $(this).css({ 
                        'background':
                        methods.gradientToString(settings.colors, settings.direction)
                    });
                } else {
                    $.error('Please pass an array');
                }

            });

        },
        gradientToString: function (colors, direction) {

            var nbColors = colors.length;

            //If no percent, we need to calculate them
            if(colors[0].percent === undefined) {

                //Passed only colors as an array we make it an object
                if(colors[0].color === undefined) {
                    var tmp = [];
                    for(i=0; i < nbColors; i++)
                        tmp.push({'color':colors[i]});

                    colors = tmp;
                }

                var p = 0,
                    percent = 100 / (nbColors - 1);

                //calculate percent
                for(i=0; i< nbColors; i++) {
                    p = i === 0 ? p : (i == nbColors-1 ? 100 : p + percent);
                    colors[i].percent = p;
                }
            }

            var to = isSafari ? '' : 'to';

            //build the string
            var gradientString = isSafari ? '-webkit-linear-gradient(' : 'linear-gradient(';

           gradientString += to +' '+ direction;

            for(i=0; i < nbColors; i++)
               gradientString += ', '+ colors[i].color + ' ' + colors[i].percent + '%';

            gradientString += ')';
            return gradientString;

        }

    };

    $.fn.gradientGenerator = function () {
        return methods.init.apply( this, arguments );
    };
})(jQuery);

例如像这样使用它：

$('.gradient').gradientGenerator({
    colors : ['#2E2E28', '#4D4C48']
});

$('.change-color').on('click', function(e) {

    e.preventDefault();
    $('.gradient').gradientGenerator({
        colors : [{color:'#4D4C48',percent:0}, {color:'#282827', percent:30}, {color:'#2E2E28', percent: 100}],
        direction : 'left'
    });

});

看到它在这里工作。

于 2013-04-25T15:57:35.547 回答
0

基于 Barney 的出色回答，这里有一个小的 jQuery 插件：

(function($) { 

  $.fn.cssGradient = function(options) {

    // support multiple elements

    if(this.length > 1){
      this.each(function(){
        $(this).cssGradient(options);
      });
      return this;
    }

    // private variables

    var that = this;

    var metaData = {};
    metaData['version'] = "1.0.0";

    // settings

    // Extend our default options with those provided.
    // Note that the first argument to extend is an empty
    // object – this is to keep from overriding our "defaults" object.

    var defaultOptions = {
          background:'',
          color1:'',
          color2:''
        }

    var settings = $.extend({},defaultOptions,options);

    // private methods

    var init = function() {
      start();
      return that;
    }

    var start = function(){
      var element = jQuery(that);
      var attr = element.attr('style');
      var style = "";
      if (typeof attr !== typeof undefined && attr !== false) {
        style = element.attr('style') + makeGradientStyle(settings.background,settings.color1,settings.color2);
      }
      else{
        style = makeGradientStyle(settings.background,settings.color1,settings.color2);
      }
      element.attr('style',style);
    }

    var makeGradientStyle = function(background,color1,color2){
      var gradientString = 'background:{background};background-image:-moz-linear-gradient(top,{color1} 0%,{color2} 100%);background-image:-o-linear-gradient(top,{color1} 0%,{color2} 100%);background-image:-webkit-linear-gradient(top,{color1} 0%,{color2} 100%);background-image:-ms-linear-gradient(top,{color1} 0%,{color2} 100%);background-image:linear-gradient(to bottom,{color1} 0%,{color2} 100%);';
      return gradientString.replace(/\{background\}/g,background).replace(/\{color1\}/g,color1).replace(/\{color2\}/g,color2);
    }

    // public methods

    this.version = function() {
      console.log('cssGradient plugin version: ',metaData['version']);
    };

    return init();

  }

})(jQuery);

并实施：

var cssGradient = jQuery('.foo').cssGradient({background:'#fff',color1:'#fff',color2:'#ff0000'});
于 2017-09-05T17:36:39.717 回答